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riadik2000 [5.3K]
2 years ago
8

Please help me on this problem!​

Mathematics
1 answer:
Airida [17]2 years ago
7 0
y = - 1/2

hope that helps
You might be interested in
What is the height of the cone below?<br><br> V = 45 in^3<br><br> B = 5in^2
Lapatulllka [165]

Answer:

The height of the cone is h = 27

Step-by-step explanation:

<u>Formula:</u>-

Step 1:-

The volume of the cone is  V=\frac{1}{3} (base)(height)

Given volume is V= 45 in^ 3

Given base of the cone is B= 5 in^2

<u>Step 2</u>:-

by using formula, we get solution

45 = \frac{1}{3} (5)(h)

cross multiplication, we get

\frac{45 x 3}{5} =h

now simplification, the height of the cone is h = 27

7 0
3 years ago
What is the probability of picking a 7 from a standard deck of 52 cards?
BARSIC [14]

Answer:

(c)- 4/13

Step-by-step explanation:

There are 4 types of cards in a ordinary deck clovers, diamands, hearts, and spades

each set has 1 seven each, so 4 sevens total.

Also, each type of card has 13 different cards in it

so, your answer is 4/13

8 0
3 years ago
Graph -3.5 and -1.5 on the number line.
faust18 [17]

Answer:

ok i kow this hold on

Step-by-step explanation:

6 0
3 years ago
Can some break this down step by step please I'm confused?​
frutty [35]

take 16+5=21. 29-21=8 so answer is 8

5 0
3 years ago
Create an equation that matches this table
Radda [10]

The equation that matches the given table is

y = 10x + 40

Solution:

General equation of a line : y = mx + c

Let us find the equation of the table.

<u>Common differences of X: </u>

0 – 1 = 1, 1 – 2 = 1, 3 – 2 = 1, 4 – 3 = 1, 5 – 4 = 1

<u>Common differences of Y: </u>

50 – 40 = 10, 60 – 50 = 10, 70 – 60 = 10, 80 – 70 = 10, 90 – 80 = 10

$m=\frac{\Delta y}{\Delta x}

$m=\frac{10}{1}

m = 10

Substitute m = 10 in general equation of a line

y = 10x + c

To find the constant term, substitute x = 0 and y = 40.

40 = 10(0) + c

40 = 0 + c

40 = c

c = 40

Therefore the equation of a line is y = 10x + 40.

Hence the equation that matches the given table is y = 10x + 40.

6 0
2 years ago
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