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3 years ago

Find the value of B of the shape

Mathematics

1 answer:

Dahasolnce [82]3 years ago

7 0

Answer:

Step-by-step explanation:

All angles of a triangle add up to 180 degrees so you would subtract from 180 with the angles you already have to get your answer. 180 - 115 - 31 = B which is 34.

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Please help! Thank you!

Ivan

Answer:

Its A

Step-by-step explanation:

8 0

3 years ago

3 (5 + 6)

ELEN [110]

Hi there!

Distributive property are two big words that basically just mean you need to distribute the 3 to the whole parentheses. This means you need to multiply 5 by 3 and also 6 by 3.

3 × 5 = 15

3 × 6 = 18

Now that you've distributed the 3 to the entire parentheses, you just need to add together both answers you got :

15 + 18 = 33

Your answer is: 33

There you go! I really hope this helped, if there's anything just let me know! :)

4 0

3 years ago

Work out the percentage change to 2 decimal places when a price of £110 is decreased to £98.

djyliett [7]

Answer:

10.91% decrease

Step-by-step explanation:

98/110 x 100 = 89.090909

100 - 89.0909 = 10.909090 to 2dp is 10.91%

8 0

3 years ago

The manufacturer of an airport baggage scanning machine claims it can handle an average of 553 bags per hour. (a-1) At α = .05 i

timurjin [86]

Answer:

H1 : μ < 553. Reject H1 if tcalc > –1.753.

There is not enough evidence to reject the manufacturer’s claim.

Step-by-step explanation:

We are given that the manufacturer of an airport baggage scanning machine claims it can handle an average of 553 bags per hour.

A sample of 16 randomly chosen hours with a mean of 533 and a standard deviation of 47 is given.

Let $\mu$ = average bags that an airport baggage scanning machine can handle.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 553 bags {means that the manufacturer’s claim is not overstated}

Alternate Hypothesis, $H_0$ : $\mu$ < 553 bags {means that the manufacturer’s claim is overstated}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 533 bags

s = sample standard deviation = 47

n = sample of hours = 16

So, the test statistics = $\frac{533-553}{\frac{47}{\sqrt{16} } }$ ~ $t_1_5$

= -1.702

The value of t test statistics is -1.702.

Now, at 0.05 significance level the t table gives critical value of -1.753 at 15 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.702 > -1.753, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the manufacturer’s claim is not overstated and an airport baggage scanning machine can handle an average of 553 bags per hour.

5 0

3 years ago

There are 180 school days in a year. How many days are in 5 years

labwork [276]

There are 180 school days in a year. How many school days are in 5 years?

If we know that there are 180 school days in 1 year, we can multiply 180 by 5 to get our answer of how many school days are in 5 years.

900 school days in 5 years.

5 0

3 years ago