R(x) = 60x - 0.2x^2
The revenue is maximum when the derivative of R(x) = 0.
dR(x)/dx = 60 - 0.4x = 0
0.4x = 60
x = 60/0.4 = 150
Therefore, maximum revenue is 60(150) - 0.2(150)^2 = 9000 - 4500 = $4,500
Maximum revenue is $4,500 and the number of units is 150 units
There approximately 7133 books in the library;
Data;
- Let the number of total books = x
- Number of fictional books = 3/4x
<h3>Word Problem</h3>
To solve this problem, we simply need to use an equation to explain the word problem into mathematical statements.
Let the total number of books be represented by x
The number of fictional books = 3/4x
After 592 fictional books were donated;

Let collect like terms and solve

There approximately 7133 books in the library;
Learn more on word problems here;
brainly.com/question/13818690
4* 59+ 10= 246
The 59th term is 246~
Answer:
x = -2/5
x = 1
Step-by-step explanation:
5x² - 3x - 2 = 0
(5x + 2)(x - 1) = 0
⇒ 5x + 2 = 0
⇒ 5x = -2
⇒ x = -2/5
⇒ x - 1 = 0
⇒ x = 1
Answer:
Infinitely many
Step-by-step explanation:
12x+1=3(4x+1)-2
Expand 3(4x+1)-2
12x+3-2
12x+1
12x+1=12x+1
Simplify.
0=0
True for all values of x