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Lilit [14]
3 years ago
5

4. Un cuadrado tiene un área de 400 cm2; si se aumenta un centímetro por lado, ¿cuál será el perímetro del nuevo cuadrado?

Mathematics
1 answer:
CaHeK987 [17]3 years ago
6 0

Step-by-step explanation:

I can't read Spanish or read Spanish I'm sorry

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The statistical difference between a process operating at a 5 sigma level and a process operating at a 6 sigma level is markedly
Svet_ta [14]

Answer:

True

Step-by-step explanation:

A six sigma level has a lower and upper specification limits between \\ (\mu - 6\sigma) and \\ (\mu + 6\sigma). It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:

\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027

For those with defects <em>operating at a 6 sigma level, </em>the probability is:

\\ 1 - p = 1 - 0.999999998027 = 0.000000001973

Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:

\\ p = F(\mu + 5\sigma) - F(\mu - 5\sigma) = 0.999999426697.

The probability of defects is:

\\ 1 - p = 1 - 0.999999426697 = 0.000000573303

Well, the defects present in a six sigma level and a five sigma level are, respectively:

\\ {6\sigma} = 0.000000001973 = 1.973 * 10^{-9} \approx \frac{2}{10^9} \approx \frac{2}{1000000000}

\\ {5\sigma} = 0.000000573303 = 5.73303 * 10^{-7} \approx \frac{6}{10^7} \approx \frac{6}{10000000}  

Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>

\\ {6\sigma} \approx \frac{2}{10^9} [1]

\\ {5\sigma} \approx \frac{6}{10^7} = \frac{6}{10^7}*\frac{10^2}{10^2}=\frac{600}{10^9} [2]

Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.

8 0
3 years ago
Manny makes dinner using 1 box of pasta and 1 jar of sauce. if pasta is sold in packages of 6 boxes and sauce is sold in package
kiruha [24]
The least amount of dinners that Manny can make without any supplies leftover is 3
3 0
4 years ago
Read 2 more answers
Which expression uses the greatest common factor and the distributive property to rewrite the sum 7 + 75
Lady_Fox [76]

Answer:

75 + 45 = 15(3 + 5)

Step-by-step explanation:

Given

75 + 45 <em>-- Corrected</em>

Required

Use the GCF to write it as a distributive property

First, we find the GCF of 75 and 45

45 = 3 * 3 * 5

75 = 3 * 5 * 5

The common factor is:

GCF = 3 * 5

GCF = 15

So, 75 + 45 becomes

75 + 45 = 15 * 3 + 15 * 5

Factorize

75 + 45 = 15(3 + 5)

<em>Hence, the sum has been rewritten as </em>15(3 + 5)<em></em>

5 0
3 years ago
I need help with 24 plzz
e-lub [12.9K]

Answer: -60

Step-by-step explanation:

5 - 1/3x = -15

-1/3x = -20

(-3/1)-1/3x=-20(-3/1)

x = -60

8 0
3 years ago
What is different between solving inequalities and absolute value inequalities?
Ivenika [448]

Answer:

The absolute number of a number a is written as

|a|

And represents the distance between a and 0 on a number line.

An absolute value equation is an equation that contains an absolute value expression. The equation

|x|=a

Has two solutions x = a and x = -a because both numbers are at the distance a from 0.

To solve an absolute value equation as

|x+7|=14

You begin by making it into two separate equations and then solving them separately.

x+7=14

x+7−7=14−7

x=7

or

x+7=−14

x+7−7=−14−7

x=−21

An absolute value equation has no solution if the absolute value expression equals a negative number since an absolute value can never be negative.

The inequality

|x|<2

Represents the distance between x and 0 that is less than 2

Whereas the inequality

|x|>2

Represents the distance between x and 0 that is greater than 2

You can write an absolute value inequality as a compound inequality.

−2<x<2

This holds true for all absolute value inequalities.

|ax+b|<c,wherec>0

=−c<ax+b<c

|ax+b|>c,wherec>0

=ax+b<−corax+b>c

You can replace > above with ≥ and < with ≤.

When solving an absolute value inequality it's necessary to first isolate the absolute value expression on one side of the inequality before solving the inequality.

Step-by-step explanation:

Hope this helps :)

5 0
3 years ago
Read 2 more answers
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