The area of each triangular face is
.. A = (1/2)*b*h
.. Aside = (1/2)*(6 cm)*(5 cm) = 15 cm^2
The area of the triangular base is
.. Abase = ((√3)/4)*s^2 = (√3)/4*(6 cm)^2 = 9√3 cm^2
The total surface area is the base area plus the area of the three sides.
.. Atotal = Abase + 3*Aside
.. = 9√3 cm^2 +3*15 cm^2
.. = (45 +9√3) cm^2
.. ≈ 60.6 cm^2
Actually, there's an error in the picture. The height of the side should be 4, and the length of the edge should be 5. Making that adjustment, the total area is 51.6 cm^2.
It is hard to tell what is intended. Not all answers are showing, so we can't "reverse-engineer" the problem from the answers.
x -y = 1
5x + 3y = 45
Solve the first equation for x: x = y + 1
Substitute x in the second with y + 1
5x + 3y = 45
5(y + 1) + 3y = 45
5y + 5 + 3y = 45
8y + 5 = 45
8y = 40
y = 5
Substitute 5 for y in x = y + 1
x = y + 1
x = 5 + 1
x = 6
Answer: (6, 5)
Answer:
B(6 , -11)
Step-by-step explanation:
(x-2 , y+3) = (4 , -8)
Compare the x & y co ordinates
x - 2 = 4 ; y + 3 = -8
x = 4 +2 ; y = -8 - 3
x = 6 ; y = -11
B(6 , -11)
