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Vaselesa [24]
3 years ago
12

You have 12 gallons of a 20% alcohol racing fuel mixture. You want to add

Mathematics
1 answer:
Marysya12 [62]3 years ago
4 0
Djdoxjxidkdidkdkkdkdkd
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Witch of these has a slope of -3/4 and a y intercept of 3/2
Arada [10]

Answer:

See explanation. (Also you can write an equation several different ways so without the choices I cannot tell you which)

Step-by-step explanation:

Slope-intercept form is y=mx+b

So one way to write the equation is y=-3/4 x +3/2

There are more ways to write it.

Every line about to write is a way to write it.

Multiply both sides by 4:                 4y=-3x+6

Add 3x on both sides:               3x+4y=6

Subtract 6 on both sides:         3x+4y-6=0

There are a lot of ways to write an equation like this.

To better assist you I would need to see options.

5 0
3 years ago
What is the simplest form of 8/28?
Marizza181 [45]
2/7 because both 8 and 28 are divisible by 4
5 0
3 years ago
Read 2 more answers
What is f(g(x)) for x > 5?
mel-nik [20]

Answer:

\large\boxed{B.\ 4x^2-41x+105}

Step-by-step explanation:

f(x)=4x-\sqrt{x}\\\\g(x)=(x-5)^2\\\\f(g(x))\to\text{put}\ x=(x-5)^2\ \text{to}\ f(x):\\\\f(g(x))=f\bigg((x-5)^2\bigg)=4(x-5)^2-\sqrt{(x-5)^2}\\\\\text{use}\\(a-b)^2=a^2-2ab+b^2\\\sqrt{x^2}=|x|\\\\f(g(x)=4(x^2-2(x)(5)+5^2)-|x-5|\\\\x>5,\ \text{therefore}\ x-5>0\to|x-5|=x-5\\\\f(g(x))=4(x^2-10x+25)-(x-5)\\\\\text{use the distributive property:}\ a(b+c)=ab+ac\\\\f(g(x))=(4)(x^2)+(4)(-10x)+(4)(25)-x-(-5)\\\\f(g(x))=4x^2-40x+100-x+5\\\\\text{combine like terms}\\\\f(g(x))=4x^2+(-40x-x)+(100+5)\\\\f(g(x))=4x^2-41x+105

6 0
3 years ago
Read 2 more answers
fabiana decides to save the money she is earning from her after school job for college. she makes an initial contribution of 300
Oxana [17]

Answer:

A. Total Money Contributed after n months = \$ 3000 + \$ (500\times n)

B. Total Money Contributed after 24 months = \$ \ 15000

Step-by-step explanation:

Given:

Initial contribution = \$\ 3000

each month contribution =\$\ 500

After 1 month contributed = \$\ 3000 + \$\ 500 \times 1= \$ \ 3500

Solving for Part A

let n be the number of months

∴ Total Contribution after n months = Initial contribution + (each month contribution \times Number of months = \$\ 3000 + \$\ 500 \times n

Solving for Part A

Now n= 24 months

∴ Total Contribution after 24 months = \$\ 3000 + \$\ 500 \times 24 = \$\ 3000 + \$\ 12000= \$\ 15000

3 0
3 years ago
The triangles below are similar; find the correct value of x. If necessary, round to the nearest tenths place.
Alekssandra [29.7K]
Where the triangle at?
4 0
2 years ago
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