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3 years ago

What gave George W Bush an advantage in the election of 1988?

Advanced Placement (AP)

1 answer:

svetlana [45]3 years ago

7 0

The correct answer to this open question is the following.

Although there are no options attached we can say the following.

What gave George W Bush an advantage in the election of 1988 was that he showed more poise, balance, and experience than his rival, Democrat Michael Dukakis.

During his political campaingm}, Republican candidate George H. W. Bush promised not to raise taxes, something that really appeal to his Republican and conservative followers. He promised to have a George H. W. Bush had a more conciliatory approach in his relationship to Middle East foreign affairs.

However, during his administration, he had to break his promise of not raising taxes and that really disappointed the American people.

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Which of the following best describes the impact of national campaigns on the elections process?

gregori [183]

Answer:

Explanation:

provides framework for local level reps on a campaign strategy. Think about Trump and how he made local level candidates talk about him in there speeches

6 0

3 years ago

Read 2 more answers

How do you convince your parents to let you do fashion designing for a living if they chose my career path for me?

bezimeni [28]

Tell them what you want. Become more responsible and make sure you have their trust. Tell them that this is what you really want to do and that you won’t let them down. Good luck

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3 years ago

ASAP PLSS HELP ME <br> How do you receive criticism?

levacccp [35]

Bad answer but here goes:

1. Stop Your First Reaction. ...

2. Remember the Benefit of Getting Feedback. ...

3. Listen for Understanding. ...

4. Say Thank You. ...

5. Ask Questions to Deconstruct the Feedback. ...

6. Request Time to Follow Up.

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4 years ago

Hello, I need help with a calculus FRQ. My teacher has given a hint that this last part has to do with the intermediate value th

lesya [120]

Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

Explanation:

To answer the question

Therefore, where the domain of the function is the set of all real numbers x for which f(x) is a real number we have

For Chloe's velocity

$C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2$

Finding the boundaries of the function gives;

$0\times e^{4-0^2} = 0$ and $2\times e^{4-2^2} = 2$

At t = 1, we have $1\times e^{4-1^2} = e^{3} = 20.086$

We find the maximum point as follows;

$\frac{\mathrm{d} \left (t\times e^{4-t^2} \right )}{\mathrm{d} x}=0$

From which we have;

$\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0$

$e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0$

$e^{4-t^2}(1 - t\times2\times t })=0\\e^{4-t^2}(1 - 2\times t^2 })=0\\$

$e^{4-t^2}=0$ or $(1 - 2\times t^2 })=0$

∴ 1 = 2·t² and from which t = (√2)/2

Hence the function C(x) is decreasing from t = (√2)/2 to t = 2

For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

Given that the function B(t) is differentiable, therefore, continuous, there exists a point at which the function C(t) and B(t) intersects given that;

For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

and for 0 ≤ t ≤ 0 1 ≤ B(t) ≤ 8 and for 1 < t ≤ 2, 8 > B(t) ≥ 1.5

Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

8 0

3 years ago

A ball is projected upward at time t = 0 s, from a point on a flat roof 10 m above the ground. The ball rises and then falls wit

Arisa [49]

<span>We can use a simple kinematic equation to find the velocity of the ball. v = v0 + at v = 58.5 m/s + (-9.80 m/s^2) (5.97 s) v = -0.006 m/s The negative sign means that the ball is heading down toward the ground. The small magnitude of the velocity means that the ball has reached the maximum height and is starting to fall back down toward the ground. The velocity of the ball is -0.006 m/s</span>

5 0

4 years ago