The given 2 cm is the length of the arc that the second hand had traveled for 15 seconds. Since the second hand completes a whole revolution in 60 seconds, it traveled approximately 1/4 of its circumference for 15 seconds. The length of the second hand is the radius of the circle.
2 cm = (1/4) x 2π x (L)
Solving for L gives an answer of 1.273 cm. Thus, the answer is the second choice, 1.3 cm.
Answer:
x1, x2 = 7.73 , 4.27
Step-by-step explanation:
To find the roots of a quadratic function we have to use the bhaskara formula
ax^2 + bx + c
x^2 - 12x + 33
a = 1 b = -12 c = 33
x1 = (-b + √ b^2 - 4ac)/2a
x2 =(-b - √ b^2 - 4ac)/2a
x1 = (12 + √(-12^2 - (4 * 1 * 33))) / 2 * 1
x1 = (12 + √(144 - 132)) / 2
x1 = (12 + √12) / 2
x1 = (12 + 3.46) / 2
x1 = 15.46 / 2
x1 = 7.73
x2 = (12 - √(-12^2 - (4 * 1 * 33))) / 2 * 1
x2 = (12 - √(144 - 132)) / 2
x2 = (12 - √12) / 2
x2 = (12 - 3.46) / 2
x2 = 8.54 / 2
x2 = 4.27
Answer:
Completing the square.
Step-by-step explanation:
since there is no "a" term and the bx term is even, completing the square is your best bet.
Answer:
67.5
Step-by-step explanation:
135/2=67.5
answer is $67.50
The trick with this problem is that there is no trick - there's no math involved at all, just wordplay. The key is in one-time deposit; what you're looking for isn't a recurring fee, but rather a constant. Now, an equation is made up of three things:
- a variable
- a relational statement in the form of =
- a constant, even if it isn't really there, it's zero
In this case, what you're looking for is the constant in the equation; a value that doesn't change when any variable changes.
The only number in your question that fits the bill is 1200$, since it's a <em>one-time, unchanging value.</em> <em>y </em>is the total amount paid and x represents the months, which are both variables; 400 is tied to x, so it also changes based on months.
