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Colt1911 [192]
3 years ago
11

What is the area of the trapozoid?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer:

8units²

Step-by-step explanation:

area of trapezoid=½(a+b)*h

a=2

b=6

h=2

area of trapezoid=½(2+6)*2

area of trapezoid=½(8)*2

area of trapezoid=4*2

=8units²

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3x^2+7x+3<br> + 5x^2+12x
Dvinal [7]

Answer:

8x^2+19x

Step-by-step explanation:

Simplify the expression by combining like terms. Terms which look a like and sound a like should be added together.

3x^2+7x+3+5x^2+12x

x^2 terms: 3x^2+5x^2=8x^2

x terms: 7x+12x=19x

constants: 3

Together is is 8x^2+19x+3.

5 0
3 years ago
Read 2 more answers
Calculate the slope, or rate of change, of this line.<br><br> 1) 3<br> 2) 4<br> 3) 2<br> 4) 0.5
ASHA 777 [7]

Answer:

The slope for the line is 2

7 0
3 years ago
Which is greater than, less than, and equal to 18 tons or 36,000 lbs?
slamgirl [31]
36000 lbs = 16329.325 kg
18 ton = 18000kg

18 ton is greater
5 0
3 years ago
If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e
Pepsi [2]

The outlier of a dataset is a data element that is relatively far from the remaining data elements

  • <em>99 is an outlier of pet group</em>
  • <em>See attachment for the parallel box plots</em>

<u>(a) Prove that 99 is an outlier for Pet</u>

We have:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

n = 15

The quartiles positions are:

Q_1 = \frac{n + 1}{4}

Q_1 = \frac{15 + 1}{4}

Q_1 = \frac{16}{4}

Q_1 = 4th

Q_3 = Q_1 \times 3

Q_3 = 4th \times 3

Q_3 = 12th

So, we have:

Q_1 = 4th

Q_3 = 12th

From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

Q_1 = 68

Q_3= 79

The lower and upper limits of the outlier are:

L = Q_1 - 1.5 \times (Q_3 - Q_1)

U = Q_3 + 1.5 \times (Q_3 - Q_1)

So, we have:

L = 68 - 1.5 \times (79 - 68)

L = 51.5

U = 79+ 1.5 \times (79 - 68)

U = 95.5

This means that data below 51.5 or above 95.5 are outliers.

<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>

<u>(b) The parallel box plot</u>

The three groups are:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>

<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>

<em />

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

5 0
3 years ago
Sarah sights the top of the statue of liberty at an angle of elevation of 61 if sarah is 5.5 feet tall and is standing 166 feet
vovangra [49]
To solve this problem you must apply the proccedure below:

 1. You have that:

 - Sarah sights the top of the statue of liberty at an angle of elevation of 61°.

 - She is standing 166 feet from the base of the statue.
<span>
 - Sarah is 5.5 feet tall.

 2. Therefore, the heigth of the statute is:

 Tan(61°)=x/166
 x=(166)(</span>Tan(61°)
 x=299.47 feet

 Height of the statue=299.47 feet+5.5 feet
 Height of the statue=304.97 feet
6 0
3 years ago
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