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aksik [14]
4 years ago
13

Please help me with this question

Mathematics
1 answer:
Kobotan [32]4 years ago
6 0
Is that delta math I never understand the math problems from there
You might be interested in
Find the LCM of 14ab2c3 and 35a2b3c<br> Please list the multiples with it
soldier1979 [14.2K]

Answer:

The LCM is 70a^2b^3c^3

Step-by-step explanation:

To find the LCM, we find the prime factorization of each expression.

For the first expression, we have

14ab^2c^3=2\times7\times a\times b^2\times c^3

For the second expression, we have

35a^2b^3c=5\times 7\times a^2\times b^3 \times c

For the LCM, we multiply the highest powers common to both prime factorization.

The Least Common Multiple is

=2\times 5\times 7\times a^2\times b^3 \times c^3

=70a^2b^3c^3

7 0
3 years ago
Is the perpendicular bisector of . What is the length of ?
mixas84 [53]

Answer:

the answer is C. 12

Step-by-step explanation:

5 0
3 years ago
The fencing of the left border costs $4 per foot, while the fencing of the lower border costs $1 per foot. (no fencing is requir
lord [1]
<span><u>Answer </u>
Left border = 8 feet
Lower border =32 feet
Area=128 〖ft〗^2


<u>Explanation </u>
The area is a right triangle.
Let us take the left border to be y feet and the lower border to be x feet
Area=1/2 yx
The cost of fencing would be 4y+x=64.
From this expression x=64-4y
Substituting this value of x in the area we have;
Area=1/2 y(64-4y)
A=32y-2y^2
To get the maximum area of the triangle the first derivative of the area would te equal to zero.
A=32y-2y^2
dA/dy=32-4y=0
4y=32
y=8
Since x=64-4y
x=64-(4×8)=32
The dimensions of the garden are 8 feet by 32 feet.
Since the garden is a right triangle,
Area=1/2×8×32
Area=128 〖ft〗^2 
</span>
3 0
3 years ago
Please help me I don’t understand this
Vitek1552 [10]

Answer:

14/15

Step-by-step explanation:

9/15+5/15=14/15

3 0
3 years ago
Read 2 more answers
Help me please!!!!!! It’s math btw.
FrozenT [24]
1.  The 5/65 can be simplified, the a³ moves to the denominator, and bc is canceled from the numerator and denominator.
\frac{5a^3 bc^2}{65 a^4 bc} = \frac{c}{13a}

2.  The 10/125 can be simplified, the a³ moves to the denominator, and bc is canceled from the numerator and denominator.
\frac{10a^3bc^2}{125a^4bc} = \frac{2c}{25a}

3.  The 65/5 simplifies, the a³ moves to the numerator, and bc is canceled from the numerator and denominator.
\frac{65a^4 bc^2}{5a^3 bc} = 13ac

4.  The 10/130 simplifies, the b² cancels out in the numerator and denominator, and the c^4 moves to the numerator.
\frac{10b^2 c^5}{130a^4b^2c^4} = \frac{c}{13a^4}

5.  The 10/130 simplifies, the b² cancels out in the numerator and denominator, the a^4 moves to the numerator, and the c^4 moves to the numerator.
\frac{10a^5b^2c^5}{130a^4b^2c^4} = \frac{ac}{13}


I believe the only expression that simplifies to \frac{c}{13a} is the first one.
7 0
3 years ago
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