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goblinko [34]
3 years ago
8

Which of the following values are solutions to the inequality –8 + 2x > 5

Mathematics
1 answer:
myrzilka [38]3 years ago
3 0

Answer:

6

Step-by-step explanation:

i guess

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A food store makes a 11–pound mixture of peanuts, almonds, and raisins. The cost of peanuts is $1.50 per pound, almonds cost $3.
arlik [135]
Given: 11-pound mixture of peanuts, almonds, and raisins
Cost:
peanuts - 1.5 per pound
almonds - 3 per pound
raisins - 1.5 per pound

mixture:
twice as many peanuts as almond; total cost of mixture is 21.

a + p + r = 11 lbs
a + 2a + r = 11 lbs
3a + r = 11
r = 11 - 3a

1.5(2a) + 3a + 1.5r = 21
3a + 3a + 1.5r = 21
6a + 1.5r = 21
6a + 1.5(11-3a) = 21
6a + 16.5 - 4.5a = 21
6a - 4.5a = 21 - 16.5
1.5a = 4.5
1.5a/1.5 = 4.5/1.5
a = 3

almonds = 3 lbs
peanuts = 2a = 2(3) = 6lbs
raisins = 11 - 3a = 11 - 3(3) = 11 - 9 = 2 lbs

<span>My answer is: C. 6 lbs peanuts, 3 lbs almonds, 2 lbs raisins </span>
8 0
3 years ago
Read 2 more answers
help me please!!!!!! I really need help
IRINA_888 [86]

Answer:

Part A: hx2=a

Part B: 5hours

Step-by-step explanation:

7 0
2 years ago
How much taller is a meter stick than 65 cm<br><br><br> will mark as brainiest
Lisa [10]

Answer:

it's 13 meters taller

Step-by-step explanation:

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7 0
3 years ago
Two cross roads, each of width Sm, run at right angles through the
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Answer:

Rs 57750

Step-by-step explanation:

width =5 m

length of first parallel road 70 m

area of first road 70×5=350 sq.m

length of second road 45 m

area of second road =45×5=225 sq.m

area of the common part of cross road with 5 m width that lies at the

center of the park 5×5 = 225 sq.m

area of roads = area of first road +area of second cross road−common area

=(350+225)−25

=575−25

=550sqm

​

cost of the construction per sq.m =Rs.105

total cost =550×105=Rs 57750

7 0
2 years ago
2over 8 minutes seven fourths
mezya [45]
The answer is 1/2 hope it helps
8 0
3 years ago
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