MATH 10 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

What are the ratio of 18 red button ; 12 red button?

Daniel [21]

The right answer is 3:2

7 0

3 years ago

to arrive at 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution. How many liters of eac

CaHeK987 [17]

Answer:

800 liters of 90% saline solution and 1200 liters of 40% saline solution should be used.

Step-by-step explanation:

Given:

At 2000 liters of 60% saline solution the attendant has to mix a 90% and a 40% saline solution.

Now, to find the number of liters of saline solution each should be used.

Let the liters of 90% saline solution mix be $x.$

And let the liters of 40% saline solution mix be $y.$

So, the total number of liters:

$x+y=2000.$

$y=2000-x\ \ \ ....(1)$

Now, the total percentage of saline solution:

$90\%\ of\ x+40\%\ of\ y=60\%\ of\ 2000$

$\frac{90}{100}\times x+\frac{40}{100}\times y=\frac{60}{100}\times 2000$

$0.9x+0.4y=1200$

Substituting the value of $y$ from equation (1) we get:

$0.9x+0.4(2000-x)=1200$

$0.9x+800-0.4x=1200$

$0.5x+800=1200$

Subtracting both sides by 800 we get:

$0.5x=400$

Dividing both sides by 0.5 we get:

$x=800.$

The liters of 90% saline solution mix = 800.

Now, substituting the value of $x$ in equation (1) to get the liters of 40% saline solution:

$y=2000-x$

$y=2000-800$

$y=1200.$

Thus, the liters of 40% saline solution = 1200.

Therefore, 800 liters of 90% saline solution and 1200 liters of 40% saline solution should be used.

8 0

4 years ago

What is the product of 4 1/6 and 2 1/5

maw [93]

Answer:

4.91

Step-by-step explanation:

4¹/6*2¹/5

25/6*11/5

275/30

4.91

5

8 0

3 years ago

I don't get this it hard!!!!!!!!!

asambeis [7]

I don't think that anybody in Elementary School would Understand this you might want to post this question in the High School section.

Hope it gets answered :)

7 0

3 years ago

Read 2 more answers

Suppose a research firm conducted a survey to determine the average amount of money steady smokers spend on cigarettes during a

olchik [2.2K]

Answer:

option (b) 0.0228

Step-by-step explanation:

Data provided in the question:

Sample size, n = 100

Sample mean, μ = $20

Standard deviation, s = $5

Confidence interval = between $19 and $21

Now,

Confidence interval = μ ± $z\frac{s}{\sqrt n}$

thus,

Upper limit of the Confidence interval = μ + $z\frac{s}{\sqrt n}$

or

$21 = $20 + $z\frac{5}{\sqrt{100}}$

or

z = 2

Now,

P(z = 2) = 0.02275 [From standard z vs p value table]

or

P(z = 2) ≈ 0.0228

Hence,

the correct answer is option (b) 0.0228

3 0

3 years ago