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RSB [31]
2 years ago
13

Please help i dont understand this problem

Mathematics
1 answer:
DaniilM [7]2 years ago
7 0

y=x+5

Step-by-step explanation:

The opposite of y is x axis

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When using a straight ladder, it is recommended that the base of the ladder by placed approximately 1/4 the length of the entire
RUDIKE [14]

Answer:

What is the question?

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
The admision fee at a basket ball game is 350$ for children and 750$ for adults. On a certain night,1500 people enter the basket
Hoochie [10]

<u>Note: The only way to solve this problem is by adjusting the fees to $3.50 and $7.50.</u>

Answer:

<em>1300 children attended the basketball game</em>

Step-by-step explanation:

System of Equations

Let's call:

x = number of children attending the basketball game

y = number of adults attending the basketball game

On a certain night, 1500 people enter the game, thus:

x + y = 1500           [1]

Since each admission fee for children cost $3.50 and $7.50 for adults and it was collected $6050, thus:

3.50x + 7.50y = 6050            [2]

From [1]:

y = 1500 - x

Substituting in [2]:

3.50x + 7.50(1500 - x) = 6050

Operating:

3.50x +  11250 - 7.50 = 6050

-4x = 6050 - 11250

Solving:

x = 1300

1300 children attended the basketball game

5 0
3 years ago
Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of
Shalnov [3]

Answer:

Owl= 67.14ft

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}

22^{\circ} 8'6'' = 22.135^{\circ}

30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}

30^{\circ} 40'30'' = 30.675^{\circ}

Considering Jason's position:

tan(22.135^{\circ}) = \frac{H}{x + 48}

Where x = distance between the tree and Alison

Make H the subject

H = (x + 48)tan(22.135^{\circ})

Considering Alison's position

tan(30.675^{\circ}) = \frac{H}{x}

Make H the subject

H = xtan(30.675^{\circ})

H = H

(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})

(x + 48) *0.4068 = x* 0.5932

Open bracket

x *0.4068 + 48 *0.4068 = 0.5932x

0.4068x + 19.5264 = 0.5932x

Collect Like Terms

-0.5932x+0.4068x = -19.5264

-0.1864x = -19.5264

0.1864x = 19.5264

Make x the subject

x = \frac{19.5264}{0.1864}

x = 104.76

Substitute 104.76 for x in H = xtan(30.675^{\circ})

H = 104.76 * tan(30.675^{\circ})

H = 104.76 * 0.5932

H = 62.14

The above represents the height of the tree.

The height of the owl is:

Owl= H + 5

Owl= 62.14 + 5

Owl= 67.14ft

7 0
2 years ago
If the area of a right triangle is 9/16 sq.ft. and the height is 3/4 ft., write an equation that relates the area to the base, b
spayn [35]
B=1/2

9/16=1/2b(3/4)

Divide both sides by 3/4

1/4=1\2b

Multiply both sides by 2
7 0
3 years ago
Read 2 more answers
A building casts a shadow 168 meters long. At the same time, a pole 5 meters high casts a shadow 20 meters long . What is the he
yawa3891 [41]

Answer:

42

Step-by-step explanation:

The height of the pole is 4 times shorter than the length of the shadow 20÷5=4

The height of the building must be 4 times shorter than its shadow length 168÷4=42

3 0
3 years ago
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