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disa [49]
3 years ago
8

Natasha places a mirror on the ground 24 ft from the base of an oak

Mathematics
2 answers:
melisa1 [442]3 years ago
8 0

Answer: 2

5.5 x 4 = 22 - 24

Kamila [148]3 years ago
6 0

Answer:

33 ft

Step-by-step explanation:

5.5/4 = x/24

x=33

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32 + x = -12<br> What is the very first step?
NISA [10]

Answer: The first step would be to subtract 32 from both sides.

Step-by-step explanation:

The answer to the whole equation is -44.

To get -44 you need to get rid of the 32 to get the x to be alone.

6 0
3 years ago
Heights of Basketball Players (inches)
uysha [10]

Answer:

Mean: 78.8

M.A.D(Mean Absolute Deviation): 2.3

Step-by-step explanation:

Mean: 73, 75, 76, 78, 78, 79, 79, 80, 81, 81, 82, 84 = 946/12 = 78.8

Mean Absolute Deviation (M.A.D):

78.8 - 73 = 5.8

78.8 - 75 = 3.8

78.8 - 76 = 2.8

78.8 - 78 = 0.8

78.8 - 78 = 0.8

78.8 - 79 = 0.2

78.8 - 79 = 0.2

78.8 - 80 = 1.2

78.8 - 81 = 2.2

78.8 - 81 = 2.2

78.8 - 82 = 3.2

78.8 - 84 = 5.2

5.8 + 3.8 + 2.8 + 0.8 + 0.8 + 0.2 + 0.2 + 1.2 + 2.2 + 2.2 + 3.2 + 5.2 = 28.4/12 = 2.3

~hope this helps~

-please mark me the brainliest if i'm correct-

6 0
3 years ago
Read 2 more answers
If F(x)=x^3+5x and G(x) =2x+1, find F(5) + G(6)​
schepotkina [342]

Answer:

F(5)+G(6)=163

Step-by-step explanation:

We were given that:

F(x)=x^3+5x and G(x)=2x+1

When x=5

F(5)=5^3+5*5

F(5)=125+25=150

When x=6

G(6)=2*6+1

G(6)=12+1=13

This implies that:

F(5)+G(6)=150+13=163

3 0
4 years ago
14. Suppose that 1 out of every 10,000 doctors in a certain region is infected with the SARS virus; in the same region, 20 out o
hram777 [196]

Answer:

The person in the at-risk population is much more likely to actually have the disease

Step-by-step explanation:

The probability of a randomly selected doctor having the disease is 1 in 1,000 (P(I)=0.0001).

The probability that a doctor is infected with SARS, given that they tested positive is:

P(I|+)=\frac{P(I)*0.99}{P(I)*0.99+(1-P(I))*0.01}\\P(I|+)=\frac{0.0001*0.99}{0.0001*0.99+(1-0.0001)*0.01}\\P(I|+)=9.9*10^{-3}

The probability of a randomly selected person from the at-risk population having the disease is 20 in 100 (P(I)=0.20).

The probability that a person in the at-risk population is infected with SARS, given that they tested positive is:

P(I|+)=\frac{P(I)*0.99}{P(I)*0.99+(1-P(I))*0.01}\\P(I|+)=\frac{0.2*0.99}{0.2*0.99+(1-0.2)*0.01}\\P(I|+)=0.962

Therefore, the person in the at-risk population is much more likely to actually have the disease

3 0
3 years ago
On Monday a local hamburger shop sold a combined total of 390 hamburgers and cheeseburgers. The number of cheeseburgers sold was
lions [1.4K]

Answer:

Hamburgers + Cheeseburgers= 390

Hamburgers= x

Cheeseburgers= 2x

2x+x= 390

3x=390

x=130

Hamburgers sold= 130

6 0
3 years ago
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