Answer:
yes
Step-by-step explanation:
yes that is true you are correct
Theory:
The standard form of set-builder notation is <span>
{ x | “x satisfies a condition” } </span>
This set-builder notation can be read as “the set
of all x such that x (satisfies the condition)”.
For example, { x | x > 0 } is
equivalent to “the set of all x such that x is greater than 0”.
Solution:
In the problem, there are 2 conditions that must
be satisfied:
<span>1st: x must be a real number</span>
In the notation, this is written as “x ε R”.
Where ε means that x is “a member of” and R means “Real number”
<span>2nd: x is greater than or equal to 1</span>
This is written as “x ≥ 1”
Answer:
Combining the 2 conditions into the set-builder
notation:
<span>
X =
{ x | x ε R and x ≥ 1 } </span>
Answer:
y = 24
Step-by-step explanation:
3x + y = 6
Solve for y
Subtract 3x from each side
3x -3x+ y = 6-3x
y = 6-3x
Let x = -6
y = 6 -3(-6)
=6+18
=24
Answer:
≈283.33333
Step-by-step explanation:
V=lwh/3
10 · 10 · 8.5 /3
<h2>≈283.33333</h2>
