Answer:
The ticket is bought for 28 students.
Step-by-step explanation:
It is given that the teacher is going to buy museum ticket for each students.
Total money spent = $182
Price of each ticket = $6.50
Let total number of tickets bought = 
We know that to find the total amount of money spent on ticket, we can add price of each ticket (i.e. $6.50) number of times.
OR
In other words, simply multiply the number of tickets with price of each ticket to find the total money spent.
Total money spent = 
We know that total money spent is $182.
The ticket is bought for 28 students
What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
Given that the first number shows up as four. The second number should be six so that the sum would be ten. Therefore, its probability should be 1/6.
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19g/1000 would be the right answer when simplified.
