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Mamont248 [21]
3 years ago
7

300x7065 A tough one can you solve it without looking the answer up or not cheating in any way

Mathematics
1 answer:
gogolik [260]3 years ago
8 0
2,119,500
explanation: you multiply
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<em>It is 4 since 6 * 4 = 24
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15 POINTS IF YOU GET IT RIGHT I WILL GIVE YOU 5 STARS, A THANKS AND BRAINEIST ANSWER: Find the vertex, focus, directrix, and foc
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vertes=(0,0)

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Direction: x=-1/40

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Cathy and iris are planning trips to nine countries this year. There are 13 countries they would like to visit. They are decidin
Goshia [24]

Cathy and Iris have 259,459,200 ways to skip countries.

Data;

  • Number of countries they are planning to visit = 9
  • Number of countries they would like to visit = 13

<h3>Combination</h3>

To solve this problem, we would have to use a mathematical procedure known as combination.

Let us calculate the number of countries that would have to skip.

13 - 9 = 4

To decide which country they have to skip, it would be 4 out of 13.

x = ^1^3C_4 = \frac{13!}{4!}

Let's solve this

\frac{13!}{4!} = \frac{13*12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1}\\ \frac{13!}{4!} = 13*12*11*10*9*8*7*6*5 = 259459200 ways

Cathy and Iris have 259,459,200 ways to skip countries.

Learn more on combination here;

brainly.com/question/12468032

6 0
2 years ago
150 students in a tenth grade high school class take a survey about which video game consoles they own 60 students answer that o
Archy [21]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

150 students in a tenth grade high school class take a survey about which video game consoles they own. 60  students answer that one of their consoles is a Playstation, 50 answer that one of their consoles is an Xbox. Out  of these, there are 20 who have both systems.

Let A be the event that a randomly selected student in the class has a Playstation and B be the event that the  student has an XBOX. Based on this information, answer the following questions.

a) What is P(A), the probability that a randomly selected student has a Playstation?

b) What is P(B), the probability that a randomly selected student has an XBOX?

c) What is P(A and B), the probability that a randomly selected student has a Playstation and an XBOX?

d) What is P(A | B), the conditional probability that a randomly selected student has a Playstation given that he  or she has an XBOX?

Answer:

a) P(A) = 2/5

b) P(B) = 1/3

c) P(A and B) = 2/15

d) P(A | B) = 2/5

Step-by-step explanation:

Total no. of students = 150

No. of students having playstation = 60

No. of students having xbox = 50

No. of students who have both playstation and xbox = 20

a) What is P(A), the probability that a randomly selected student has a Playstation?

P(A) = No. of students having playstation/Total no. of students

P(A) = 60/150

P(A) = 2/5

b) What is P(B), the probability that a randomly selected student has an XBOX?

P(B) = No. of students having xbox/Total no. of students

P(B) = 50/150

P(B) = 1/3

c) What is P(A and B), the probability that a randomly selected student has a Playstation and an XBOX?

The probability that a students has a Playstation and an Xbox is given by

P(A and B) = P(A)*P(B)

P(A and B) = (2/5)*(1/3)

P(A and B) = 2/15

d) What is P(A | B), the conditional probability that a randomly selected student has a Playstation given that he or she has an XBOX?

The conditional probability is given by

P(A | B) = P(A and B)/P(B)

P(A | B) = (2/15)/(1/3)

P(A | B) = 2/5

Alternatively:

P(A | B) = P(A∩B)/P(B)

Where P(A∩B) is given by

P(A∩B) = No. of students who have both playstation and xbox/Total no. of students

P(A∩B) = 20/150

P(A∩B) = 2/15

P(A | B) = P(A∩B)/P(B)

P(A | B) = (2/15)/(1/3)

P(A | B) = 2/5

6 0
3 years ago
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