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faltersainse [42]
2 years ago
11

What fraction does not belong? 8/12 6/122/34/6​

Mathematics
1 answer:
alexira [117]2 years ago
6 0

Answer:

2/3

Step-by-step explanation:

because if you do 12 divided by 8 =1.15 and all the other one is 1.5 except 2/3

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In the figure, M and N are midpoints of RT and ST. What is the length of MN?
jok3333 [9.3K]
Length RS = 2b - 2a

Given that N is the midpoint of TS
⇒  Ratio of TN : TS = 1 : 2

\dfrac{TN}{TS}  =  \dfrac{MN}{RS}

\dfrac{1}{2}  =  \dfrac{MN}{2b-2a}

2MN = 2b - 2a

MN = b - a

Answer: b - a



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2 years ago
A circle with radius 3 with a central angle of 17/9pi radians. What is the area of the sector?
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For the function f(x) = 4x – 6, find the slope of the tangent line at x = -7.
mel-nik [20]

Answer:

f(-7)=-34

Step-by-step explanation:

f(x)=4x-6

f(-7)=4(-7)-6

f(-7)=-28-6

f(-7)=-34

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2 years ago
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3 0
2 years ago
Suppose we have 3 cards identical in form except that both sides of the first card are colored red, both sides of the second car
Nikolay [14]

Answer:

probability that the other side is colored black if the upper side of the chosen card is colored red = 1/3

Step-by-step explanation:

First of all;

Let B1 be the event that the card with two red sides is selected

Let B2 be the event that the

card with two black sides is selected

Let B3 be the event that the card with one red side and one black side is

selected

Let A be the event that the upper side of the selected card (when put down on the ground)

is red.

Now, from the question;

P(B3) = ⅓

P(A|B3) = ½

P(B1) = ⅓

P(A|B1) = 1

P(B2) = ⅓

P(A|B2)) = 0

(P(B3) = ⅓

P(A|B3) = ½

Now, we want to find the probability that the other side is colored black if the upper side of the chosen card is colored red. This probability is; P(B3|A). Thus, from the Bayes’ formula, it follows that;

P(B3|A) = [P(B3)•P(A|B3)]/[(P(B1)•P(A|B1)) + (P(B2)•P(A|B2)) + (P(B3)•P(A|B3))]

Thus;

P(B3|A) = [⅓×½]/[(⅓×1) + (⅓•0) + (⅓×½)]

P(B3|A) = (1/6)/(⅓ + 0 + 1/6)

P(B3|A) = (1/6)/(1/2)

P(B3|A) = 1/3

5 0
2 years ago
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