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aleksklad [387]

3 years ago

12

Please Answer these ASAP Find the area.

1 answer:

mestny [16]3 years ago

8 0

Answer:

polygon is regular. Round answer to the nearest tenth

Step-by-step explanation:

$36 - 6 \times = \frac{ < \sqrt{ \geqslant \binom{ | |4)6300 \times - 9x55.90660606.. \sqrt{. \geqslant 522 \sqrt[25h \\ ]{?} \times \frac{?}{?} \times \frac{?}{?} } | | \times \frac{?}{?} }{?} } }{?} \times \frac{?}{?}$

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Help needed....

LenKa [72]

The answer is C) y = 4x - 3
B and D can be eliminated by substituting 0 for x in each...the result is not -3
Now you have a 50/50 chance of getting the question correct

5 0

3 years ago

Quadratic shifted left by<br> 1 unit vertical stretch by a<br> factor of 1.

Aleksandr [31]

Answer:

1(x+1)^2

Step-by-step explanation:

8 0

3 years ago

What is the modulus after (-1+sqrt3i) gets raised to the 6th power

Eddi Din [679]

Answer:

it is b

Step-by-step explanation:

took the test

8 0

3 years ago

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NO LINKS!! Please help me with this problem

iogann1982 [59]

${\qquad\qquad\huge\underline{{\sf Answer}}}$

The given figure shows a vertical hyperbola with its centre at origin, and as we observe the figure, we can conclude that :

Length of transverse axis is :

$\qquad \sf \dashrightarrow \: 2b = 12$

$\qquad \sf \dashrightarrow \: b = 6$

length of conjugate axis is :

$\qquad \sf \dashrightarrow \: 2a = 8$

$\qquad \sf \dashrightarrow \: a = 4$

Equation of hyperbola ~

$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {b}^{2} } - \cfrac{ {x}^{2} }{ {a}^{2} } = 1$

plug in the values ~

$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {6}^{2} } - \cfrac{ {x}^{2} }{ {4}^{2} } = 1$

$\qquad \sf \dashrightarrow \: \cfrac{ {y}^{2} }{ {36}^{} } - \cfrac{ {x}^{2} }{ {16}^{} } = 1$

5 0

2 years ago

Read 2 more answers

Help 5y^5/y^3 a) 5y^2 b) 5/y^2 c) 5y^8 d) 5y

WARRIOR [948]

Answer:

a) 5y²

Step-by-step explanation:

5 divided by 1 is still 5

y^5/y^3 subtract the exponents since the base is the same

6 0

3 years ago

Read 2 more answers