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valina [46]
3 years ago
13

Show all work for each problem. Please show how you estimated your product. 0.12×105

Mathematics
1 answer:
mojhsa [17]3 years ago
3 0

Answer:

12.6

Step-by-step explanation:

The question requires you to estimate the product of 0.12 * 105

12/100 * 105  ----multiply 12 and 105

12 * 105 = 1260

Divide the answer by 100

1260/100 = 12.6

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I) -7s (S-4t-3u) <br><br><br>ii) -4c (2c-5d)<br>​
umka21 [38]
I) -7s^2+28st+21su
II) -8c^2+20cd
3 0
3 years ago
Read 2 more answers
Zoey solved the calculation 5 + 3.89 using a decimal number line. The decimal number line shows how Zoey calculated the answer.
IceJOKER [234]
Start at the point 0
Then move 5 points right because 5 is positive
The another 3.89 points right because your adding a positive number
Sooo 5 + 3.89 = 8.89

Hope this helps :D
4 0
3 years ago
-4(10-a)=36 what the steps
SpyIntel [72]

Hey there!☺

Answer:\boxed{a=19}

Explanation:

-4(10-a)=36 Equation

−4(10 − a) = 36  Simplify both sides

(−4)(10) + (−4)(−a) = 36 Distribute

−40 + 4a = 36

4a − 40 = 36

4a - 40 + 40 = 36 + 40 Add 40 to both sides

4a = 76

4a/4 = 76/4 Divide both sides by 4

76/4 = 19 Simplify 76/4

a = 19

Hope this helps!

8 0
3 years ago
Show that the equation x^4/2021 − 2021x^2 − x − 3 = 0 has at least two real roots.
andreev551 [17]

The roots of an equation are simply the x-intercepts of the equation.

See below for the proof that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

The equation is given as: \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

There are several ways to show that an equation has real roots, one of these ways is by using graphs.

See attachment for the graph of \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0}

Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)

From the attached graph, we can see that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500

This means that \mathbf{\frac{x^4}{2021} = 2021x^2 - x - 3 = 0} has at least two real roots

Read more about roots of an equation at:

brainly.com/question/12912962

6 0
3 years ago
X +y=5, 3x-2y+5=0, this is the question​
Neko [114]

Step-by-step explanation:

x+y=5

3x-2y+5=0

3x-2y= -5

x+y=5...... equation 1

3x-2y= -5....... equation 2

there fore make x the subject of the formula in equation 1

x=5-y.. equation 3

substitute equation three in equation 2

3(5-y)-2y=-5

15y-3y-2y=-5

10y=-5

divide both sides by 10

y=-5/10

y=-½

substitute y into equation 1

x+(-½)=5

x=5+½

x=5½

x=5½,y= -½

4 0
3 years ago
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