Given:
Segment MN has endpoints at M(-6, -3) and N(9,7).
Point Q lies on MN such that MQ:QN = 3:2.
To find:
The coordinates of point Q.
Solution:
Section formula: If a point divides of line segment whose end points are and in m:n, then the coordinates of that points are:
Segment MN has endpoints at M(-6, -3) and N(9,7) and Point Q lies on MN such that MQ:QN = 3:2. By using section formula, we get
Therefore, the coordinates of point Q are (3,3).
Answer:
y -3 = (-1/2)(x - 5)
Step-by-step explanation:
Slope of line: Notice that if we go from 7 to 5, the 'run' is -2 and the corresponding 'rise' from 2 to 3 is 1. Thus, the slope is m = -1/2.
Using m = -1/2 and the point (5, 3), we write the equation of this line in point-slope form as:
y -3 = (-1/2)(x - 5)
Answer:
Here ,
2x-30° +70° +x-10° = 180° ( sum of triangle is 180°)
3x+30 =180°
3x=150°
x=50°
I couldn't understand the last part, I think they are just options
The last part should be x>-9
Hope it helps!
#MissionExam001
Answer:
b
Step-by-step explanation:
b is the answer
the range is all real number