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3 years ago

Which polynomial below could produce this graph?

Mathematics

1 answer:

irina1246 [14]3 years ago

6 0

Answer:

f(x) = (x + 20)(x - 24)(x + 10)(x + 12)

Step-by-step explanation:

This is an equation of degree 4 and as the beginning of the graph descends from negative x the polynomial will have a positive leading coefficient. The graph is roughly W shaped.

It also has zeroes at x = -20,-12 ,-10 and x = 24.

So it is the first option.

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Last years sales were 13,500. Sales have increased 47 percent this year. How much is the increase

Gnesinka [82]

Multiply 0.47 with 13500

13500 x 0.47 = 6345

Add amount gotten to original amount

13500 + 6345 = 19845

Sales increase is 6345, with the total being 19845

hope this helps

3 0

3 years ago

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Salma, joe, and alan sent a total of 106 text messages during the weekend, salma sent 9 fewer messages than alan. Joe sent 3 tim

krek1111 [17]

Answer:

Salma, joe, and alan sent 14, 69, and 23 text messages respectively

Step-by-step explanation:

Given that Salma, joe, and alan sent a total of 106 text messages during the weekend, it means that

s + j + a = 106 where s, j, and a are the number of messages sent by Salma, joe, and alan respectively

Given salma sent 9 fewer messages than alan

s = a - 9

Joe sent 3 times as many messages as alan

j = 3a

hence

a - 9 + 3a + a = 106

5a - 9 = 106

5a = 106 + 9

5a = 115

Divide both sides by 5

a = 115/5

= 23

s = 23 - 9

= 14

j = 3* 23

= 69

5 0

3 years ago

On a number line, what is the unit distance between –11 and 3?

kumpel [21]

The answer is 14

explanation answer: 14

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3 years ago

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Find factors of x³+12x²-19x= -20

AleksAgata [21]

Answer:

No Factors

Step-by-step explanation:

$x^3-12x^2-19x+20 = 0\\Let \ p(x) = x^3-12x^2-19x+20$

Factors of 20 = ±1, ±2 , ±4 , ±5 , ±10 and ±20

±1, ±2 and ±3 are not the factors of given polynomial.

Putting x = 4 in the given polynomial

$p(4) = (4)^3+12(4)^2-19(4)+20\\p(4) = 64+192-76+20\\p(4) = 200$

So, x = 4 is not a factor of p(x)

Putting x = -4 in the given equation

$p(-4) = (-4)^3+12(-4)^2-19(4)+20\\p(-4) = -64+192-76+20\\p(-4) = 73$

So, x = -4 in the given equation

Putting x = 5 in the given equation

$p(5) = (5)^3+12(5)^2-19(5)+20\\p(5) = 125+300-95+20\\p(5) = 350$

So, x = 5 is not a factor of p(x)

Putting x = -5 in the given equation

$p(-5) = (-5)^3+12(-5)^2-19(-5)+20\\p(-5) = -125+300+95+20\\p(-5) = 290$

So, x = -5 is not a factor of p(x)

Putting x = 10 in the given equation

$p(10) = (10)^3+12(10)^2-19(10)+20\\p(10) = 1000+1200-190+20\\p(10) = 2030$

So, x = 10 is not a factor of p(x)

Putting x = -10 in the given equation

$p(-10) = (-10)^3+12(-10)^2-19(-10)+20\\p(-10) = -1000+1200+190+20\\p(-10) = 410$

So, x = -10 is not a factor of p(x)

Putting x = 20 in the given equation

$p(20) = (20)^3+12(20)^2-19(20)+20\\p(20) = 8000+4800-380+20\\p(20) = 12440$

So, x = 20 is not a factor of p(x)

Putting x = -20 in the given equation

$p(-20) = (-20)^3+12(-20)^2-19(-20)+20\\p(-20) = -8000+4800+380+20\\p(-20) = -2800$

So, x = -20 is not a factor of p(x)

From the above solution, we conclude that the given equation can not be factorized and thus, has no factors.

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4 years ago

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Romashka-Z-Leto [24]

Answer:

10:7, 10:5=2:1, 10:2=5,1

Step-by-step explanation:

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3 years ago

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