<u>Answer:</u>
Standard form of a line passing through (-2, 4) and having slope of -1/7 is x + 7y = 26
<u>Solution:</u>
Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7
Standard form of line passing through point ( a , b ) and having slope m is given by
(y – b) = m ( x – a) --------(1)
In our case given point is ( -2 , 4 ) and slope is -1/7 that means
a = -2 , b = 4 , m = -(1/7)
On substituting given value of a , b and m is equation (1) we get


=> 7( y - 4 ) = -x – 2
=> 7y + x = -2 + 28
=> x + 7y = 26
Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26
Answer: x = 13.4
Step-by-step explanation:
1. Subtract 90 degrees and 33 degrees to get angle X, which is 57 degrees.
2. Using Laws of Sine, plug in the known elements of the triangle:
(16) / (sin(90)) = (x) / (sin(57))
3. Cross multiply, this will leave 16sin(57) = xsin(90)
4. Divide sin(90) to the other side, leaving x = (16sin(57)) / (sin(90))
5. Plug this into a calculator and your final answer should be 13.4