Even though we are using variables, we still know that "difference" means subtraction. So, if the larger is x1 and x2, those variables go first. The smaller, y1 and y2 will go second. So our problem will look like this:
(x1 < x2 ? x2 : x1) - (y1 < y2 ? y1 : y2)
Answer:
2
Step-by-step explanation:
4x+3=x+9
4x-x=9-3
3x=6
x=6/3
x=2
The law of cosines for this particular situation is b^2 = a^2 + c^2 - 2ac cosB.
Filling in what you know, you have b^2 = 25 + 49 - [2(5)(7)-.1908], which simplifies to b^2 = 74 - 69.8092 which gives you a b^2 value of 4.1908, but you have to take the square root of that so you get a side value for b of 2.05.
