All categories

3 years ago

WILL BRAINLIST IF RIGHT (20points)

Mathematics

1 answer:

Lena [83]3 years ago

6 0

Answer:

-24.1t^2+3

Step-by-step explanation:

You might be interested in

Please say this answer fast now

ludmilkaskok [199]

Answer:

4 is the correct answer of the question

7 0

3 years ago

If 5/12 visitors are adults and 3/10 were men what fraction were men?

Zigmanuir [339]

You need to do the following equation:

(5/12)*(3/10)

5*3=15

12*10=120

15/120=5/40 of the adults who visited were men.

6 0

3 years ago

Please help thank you.

marusya05 [52]

This problem can be completed in 2 ways. Both are acceptable.

Option 1:

This is an isosceles trapezoid that can be divided into a rectangle and two congruent triangles.

The area of the rectangle is the base times the height.

$9 \times 4=36$

The area of one of the triangles is half the base times the height.

$\dfrac{1}{2} \times 5 \times 4 = 10$

The other triangle must have that area too.

$36+10+10=56$

The area is 56 square centimeters.

Option 2:

We can use the area formula for the trapezoid.

$A=\dfrac{b_1+b_2}{2} \times h$

Where $b_1$ is the length of the shorter base
and $b_2$ is the length of the longer base
and $h$ is the height.

The length of the shorter base is 9.
The length of the longer base is 9+5+5, or 19.

The height is 4.

$A=\dfrac{9+19}{2} \times 4$

$=56$

Same answer. The area is 56 square centimeters.

Both options are two acceptable ways the problem can be tackled.

7 0

3 years ago

Find the Fourier series of f on the given interval. f(x) = 1, ?7 < x < 0 1 + x, 0 ? x < 7

Zolol [24]

$f(x)=\begin{cases}1&\text{for }-7$

The Fourier series expansion of $f(x)$ is given by

$\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi x}7+\sum_{n\ge1}b_n\sin\frac{n\pi x}7$

where we have

$a_0=\displaystyle\frac17\int_{-7}^7f(x)\,\mathrm dx$
$a_0=\displaystyle\frac17\left(\int_{-7}^0\mathrm dx+\int_0^7(1+x)\,\mathrm dx\right)$
$a_0=\dfrac{7+\frac{63}2}7=\dfrac{11}2$

The coefficients of the cosine series are

$a_n=\displaystyle\frac17\int_{-7}^7f(x)\cos\dfrac{n\pi x}7\,\mathrm dx$
$a_n=\displaystyle\frac17\left(\int_{-7}^0\cos\frac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\cos\frac{n\pi x}7\,\mathrm dx\right)$
$a_n=\dfrac{9\sin n\pi}{n\pi}+\dfrac{7\cos n\pi-7}{n^2\pi^2}$
$a_n=\dfrac{7(-1)^n-7}{n^2\pi^2}$

When $n$ is even, the numerator vanishes, so we consider odd $n$ , i.e. $n=2k-1$ for $k\in\mathbb N$ , leaving us with

$a_n=a_{2k-1}=\dfrac{7(-1)-7}{(2k-1)^2\pi^2}=-\dfrac{14}{(2k-1)^2\pi^2}$

Meanwhile, the coefficients of the sine series are given by

$b_n=\displaystyle\frac17\int_{-7}^7f(x)\sin\dfrac{n\pi x}7\,\mathrm dx$
$b_n=\displaystyle\frac17\left(\int_{-7}^0\sin\dfrac{n\pi x}7\,\mathrm dx+\int_0^7(1+x)\sin\dfrac{n\pi x}7\,\mathrm dx\right)$
$b_n=-\dfrac{7\cos n\pi}{n\pi}+\dfrac{7\sin n\pi}{n^2\pi^2}$
$b_n=\dfrac{7(-1)^{n+1}}{n\pi}$

So the Fourier series expansion for $f(x)$ is

$f(x)\sim\dfrac{11}4-\dfrac{14}{\pi^2}\displaystyle\sum_{n\ge1}\frac1{(2n-1)^2}\cos\frac{(2n-1)\pi x}7+\frac7\pi\sum_{n\ge1}\frac{(-1)^{n+1}}n\sin\frac{n\pi x}7$

3 0

2 years ago

The table shows certain values of a cubic function

Nadusha1986 [10]

Considering the given table, we have that:

The function has a relative maximum when x is near 3.

As x approaches positive infinity, the value of the function approaches negative infinity.

<h3>When a function has a relative maximum?</h3>

A function has a relative maximum when it changes from increasing to decreasing.

Looking at the given table, it happens when x is near 3.

Also, looking at the table, for x > 3 the function is decreasing, hence as x approaches positive infinity, the value of the function approaches negative infinity.

More can be learned about functions at brainly.com/question/24737967

#SPJ1

3 0

2 years ago