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AleksandrR [38]
3 years ago
10

Match the following items by evaluating the expression for x = -6.

Mathematics
1 answer:
tigry1 [53]3 years ago
8 0

Answer:

What are the following items?

Step-by-step explanation:


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Qual das inequações seguintes e equivalente à inequação -2x <4?
garik1379 [7]

Answer:

I dont get your question

4 0
3 years ago
45 + 57 = x + y<br> x= 37<br> y =?
Mekhanik [1.2K]

Answer:

y = 65

Step-by-step explanation:

45 + 57 = x + y

x = 37

45 + 57 = 37 + y

45 + 57 = 102

102 = 37 + y

102 = 37 + y

-37    -37

102 - 37 = 65

37 + y - 37 = y

65 = y

y = 65

5 0
3 years ago
Read 2 more answers
Which statements are true?
Rina8888 [55]

Answer:

The first one and the last one are true (Since −6 is 6 units to the left of 0, |−6|=6 and −6 is closer to zero on the number line than −7, so |−6|<|−7|.)

Step-by-step explanation:

Absolute value is the distance to zero, and it is always positive. That means the positive and negative versions of a number have the same absolute value. That means the first one is true, and the second and third ones are false. For the last one, -6 is closer to zero, so that means it would be true (The absolute value of -6 is 6, and the absolute value of -7 is 7).

4 0
3 years ago
Which of the following statements about EF and EG is true?
Ganezh [65]

Answer:

Your answer is B

Step-by-step explanation:

If you count the units you can see that it is 7 units in length.

7 0
3 years ago
Find the sum of the convergent series. (round your answer to four decimal places. ) [infinity] (sin(9))n n = 1
Alexus [3.1K]

The sum of the convergent series \sum_{n=1}^{\infty}~(sin(1))^n is 5.31

For given question,

We have been given a series \sum_{n=1}^{\infty}~(sin(1))^n

\sum_{n=1}^{\infty}~(sin(1))^n=sin(1)+(sin(1))^2+...+(sin(1))^n

We need to find the sum of given convergent series.

Given series is a geometric series with ratio r = sin(1)

The first term of the given geometric series is a_1=sin(1)

So, the sum is,

= \frac{a_1}{1-r}

= sin(1) / [1 - sin(1)]

This means, the series converges to sin(1) / [1 - sin(1)]

\sum_{n=1}^{\infty}~(sin(1))^n

= \frac{sin(1)}{1-sin(1)}

= \frac{0.8415}{1-0.8415}

= \frac{0.8415}{0.1585}

= 5.31

Therefore, the sum of the convergent series \sum_{n=1}^{\infty}~(sin(1))^n is 5.31

Learn more about the convergent series here:

brainly.com/question/15415793

#SPJ4

7 0
1 year ago
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