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kotykmax [81]
2 years ago
7

Evaluate the piecewise function at the given values of the independent variable.

Mathematics
2 answers:
jolli1 [7]2 years ago
5 0
It’s 14 welcome have day
xxMikexx [17]2 years ago
4 0

Answer:

14

Step-by-step explanation:

no explanition

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Simplify 7-5x-(3+5x)​
galben [10]

Answer:

-10x +4

Step-by-step explanation:

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3 years ago
I am a quantity that can change or vary, taking on different values. Who am I?
Zigmanuir [339]
The answer is You are a variable
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Read 2 more answers
Solve the system of linear equations.
sweet-ann [11.9K]

Answer:

  • dependent system
  • x = 2 -a
  • y = 1 +a
  • z = a

Step-by-step explanation:

Let's solve this by eliminating z, then we'll go from there.

Add 6 times the second equation to the first.

  (3x -3y +6z) +6(x +2y -z) = (3) +6(4)

  9x +9y = 27 . . . simplify

  x + y = 3 . . . . . . divide by 9 [eq4]

Add 13 times the second equation to the third.

  (5x -8y +13z) +13(x +2y -z) = (2) +13(4)

  18x +18y = 54

  x + y = 3 . . . . . . divide by 18 [eq5]

Equations [eq4] and [eq5] are identical. This tells us the system is dependent, and has an infinite number of solutions. We can find them in terms of z:

  y = 3 -x . . . . solve eq5 for y

  x +2(3 -x) -z = 4 . . . . substitute into the second equation

  -x +6 -z = 4

  x = 2 - z . . . . . . add x-4

  y = 3 -(2 -z)

  y = z +1

So far, we have written the solutions in terms of z. If we use the parameter "a", we can write the solutions as ...

  x = 2 -a

  y = 1 +a

  z = a

_____

<em>Check</em>

First equation:

  3(2-a) -3(a+1) +6a = 3

  6 -3a -3a -3 +6a = 3 . . . true

Second equation:

  (2-a) +2(a+1) -a = 4

  2 -a +2a +2 -a = 4 . . . true

Third equation:

  5(2-a) -8(a+1) +13a = 2

  10 -5a -8a -8 +13a = 2 . . . true

Our solution checks algebraically.

6 0
3 years ago
How many x-intercepts are in the quadratic equation y = 7x2 − 2x − 1​
babunello [35]

Answer:

There are 2 x intercepts

7 0
3 years ago
Clint has to spend a minimum of $75 in order to use his coupon at the store
Colt1911 [192]
Okay what’s the rest of the question ?
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