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2 years ago

11

Solve for x round to the nearest tenth

1 answer:

loris [4]2 years ago

4 0

Answer:

5.4

Answer: The value of x rounded to the nearest tenth is 5.4.

Step-by-step explanation:

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The population of white rhinos in 2001 was 11,670. The population is declining by 9% each year. What is the population expected

aksik [14]

You see I need to know also the reproduction rate as well to equalize it. If 9% of the population declines each year from 2001 to 2021, around 21,006 would die by 2021. Which is 180% more than the population. If the reproduction rate isn't high enough to beat the declination rates, they'd be extinct by then.

6 0

3 years ago

Which is a factor of 45x^4−5x^2? Show work.<br><br><br>a. 5x+2 b. 9x−1 c. 6x+5 d. 3x−1

Lelu [443]

Answer:

d. 3x - 1.

Step-by-step explanation:

45x^4−5x^2

The GCF is 5x^2 so we have:

5x^2(9x^2 - 1)

The expression in the parentheses is the difference of 2 squares so:

= 5x^2(3x - 1)(3x + 1)

7 0

2 years ago

Acrylic spheres with diameters of 24 cm are used to make award trophies. How much acrylic is needed to make 15 trophies? Use 3.1

choli [55]

1. 27,129.6

2. 7,234.56

3. r=12

hope this helps sry if ther wrong pls don’t be mad if there right u r welcome

6 0

3 years ago

The lengths of lumber a machine cuts are normally distributed with a mean of 106 inches and a standard deviation of 0.3 inch. (

Vinvika [58]

Answer:

a) $P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

b) $z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

Step-by-step explanation:

Let X the random variable that represent the lengths of a population, and for this case we know the distribution for X is given by:

$X \sim N(106,0.3)$

Where $\mu=106$ and $\sigma=0.3$

Part a

We are interested on this probability

$P(X>106.11)$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And using this formula we got:

$P(X>106.11)=P(\frac{X-\mu}{\sigma}\frac{106.11-106}{0.3})=P(z>0.37)$

And we can find this probability with the complement rule:

$P(z>0.37)=1-P(z$

Part b

For this case we select a sample of n =44 and the new z score formula is given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score we got:

$z =\frac{106.11- 106}{\frac{0.3}{\sqrt{44}}}= 2.431$

And if we use the z score we got:

$P(z>2.431) =1-P(z$

6 0

2 years ago

Use the given data to find the equation of the regression line. examine the scatterplot and identify a characteristic of the dat

kari74 [83]

Answer:

y = 1.5x + 3.2009

Step-by-step explanation:

I plotted your points and drew a linear regression line.

Its equation is

y = 1.5x + 3.2009

The regression line ignores the fact that the points fall along a smooth curve.

A parabolic regression line fits the data much better.

The equation for that line is

y = - 0.1647x² + 4.1357x - 5.6946

It is the equation for a vertical parabola opening downward.

7 0

3 years ago