Question

What is the equation of the line that passes through the point (1, 3) and is perpendicular to the line 2x+3y=15?

Answer 1

Answer:

y = 1.5x + 1.5

Step-by-step explanation:

First, plot 2x + 3y = 15 on a graph. Then plot (1,3) on a graph. After that, draw a line that passes through (1,3) and forms 90 degrees angles with 2x + 3y = 15. Then find the equation of that line by finding the y-intercept (0, 1.5). Then head up to the intersection point (1.6153846153846, 3.9230769230769). Subtract 1.5 from y. (2.4230769230769) Then divide by 1.5 (1.6153846153846). Reverse the operations you just did (in reverse order) to get the equation y = 1.5x + 1.5.

(I don't know how to explain this too well.)

Answer 2

Answer:

y = 1.5x + 1.5

Step-by-step explanation:

First, plot 2x + 3y = 15 on a graph. Then plot (1,3) on a graph. After that, draw a line that passes through (1,3) and forms 90 degrees angles with 2x + 3y = 15. Then find the equation of that line by finding the y-intercept (0, 1.5). Then head up to the intersection point (1.6153846153846, 3.9230769230769). Subtract 1.5 from y. (2.4230769230769) Then divide by 1.5 (1.6153846153846). Reverse the operations you just did (in reverse order) to get the equation y = 1.5x + 1.5.

(I don't know how to explain this too well. Here's a graph to make more sense of it.)