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ololo11 [35]
3 years ago
14

2x+7y=11 is (-5,3) on the graph

Mathematics
1 answer:
Lelu [443]3 years ago
3 0

Step-by-step explanation:

The given equation is :

2x+7y=11

We need to tell the point (-5,3) lies on the graph of the above equation of not.

Put x = -5 and y = 3 in the LHS of the above equation.

LHS = 2x+7y

= 2(-5)+7(3)

= -10 +21

= 11

It means, when we put  x = -5 and y = 3 in the above equation, we get 11. Hence, (-5,3) lies on the graph of the equation.

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630 ft^3

Step-by-step explanation:

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3 years ago
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Answer: I think it’s 4

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6 0
2 years ago
What are the roots of the equation? x^2+24=14×
defon
\begin{gathered} x^2+24=14x \\ x^2-14x+24=0 \end{gathered}

Therefore,

\begin{gathered} x^2-14x+24=0 \\ x^2-2x-12x+24=0 \\ x(x-2)-12(x-2)=0 \\ (x-2)(x-12)=0 \\ x=2 \\ or\text{ } \\ x=12 \end{gathered}

6 0
1 year ago
The sum of three numbers in <br> g.p. is 21 and the sum of their squares is 189. find the numbers.
sashaice [31]
Let the three gp be a, ar and ar^2
a + ar + ar^2 = 21 => a(1 + r + r^2) = 21 . . . (1)
a^2 + a^2r^2 + a^2r^4 = 189 => a^2(1 + r^2 + r^4) = 189 . . . (2)
squaring (1) gives
a^2(1 + r + r^2)^2 = 441 . . . (3)
(3) ÷ (2) => (1 + r + r^2)^2 / (1 + r^2 + r^4) = 441/189 = 7/3
3(1 + r + r^2)^2 = 7(1 + r^2 + r^4)
3(r^4 + 2r^3 + 3r^2 + 2r + 1) = 7(1 + r^2 + r^4)
3r^4 + 6r^3 + 9r^2 + 6r + 3 = 7 + 7r^2 + 7r^4
4r^4 - 6r^3 - 2r^2 - 6r + 4 = 0
r = 1/2 or r = 2
From (1), a = 21/(1 + r + r^2)
When r = 2:
a = 21/(1 + 2 + 4) = 21/7 = 3
Therefore, the numbers are 3, 6 and 12.
3 0
3 years ago
The length of a rectangle is 5 less than twice the width. If the perimeter of the rectangle is 146 cm, find the dimensions of th
Marta_Voda [28]

Length = 2x - 5

Width = x

Perimeter = 146

P = 2L + 2W

146 = 2(2x - 5) + 2x

146 = 4x - 10 + 2x

146 = 6x - 10

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156 = 6x

156/6 = x

26 = x

Length = 2(26) - 5

Length = 52 - 5

Length = 47 cm

Width = x

Width = 26 cm

Did you follow?

4 0
3 years ago
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