All categories

3 years ago

Can you help me solve this question?

Mathematics

2 answers:

Olin [163]3 years ago

3 0

The y- intercept is 4. M= 2/3

Tema [17]3 years ago

3 0

The y intercept is 4. M=2/3

You might be interested in

Suppose a basketball player has made 217 out of 302 free throws. If the player makes the next 3 free throws, I will pay you $23.

Anna [14]

Answer:

-$0.90

Step-by-step explanation:

There are only two possible outcomes, winning $23 (W) or losing $15 (L). Therefore:

$P(W) + P(L) = 1$

The probability of the player making his next 3 free throws (P(W)) is:

$P(W) = \frac{217}{302}*\frac{217}{302}*\frac{217}{302}\\P(W) = 0.37098$

The probability of the player NOT making his next 3 free throws (P(L)) is:

$P(L) = 1 - P(W) = 1 - 0.37098\\P(L) = 0.62902$

Expected value (EV) is given by the payoff of each outcome multiplied by its probability:

$EV = (23*0.37098) -(15*0.62902)\\EV = -\$0.90$

The expected value of the proposition is -$0.90

6 0

3 years ago

Directions for (1-5): Plot the following on a number line 0.75 1.5 -2 ¾ -3 ⅕ 6.8

lana [24]

Answer:

|---|--------|---------|------|---------|-|

-2 ¾ -3 ⅕ 0.75 1.5 6.8

(This is a rough answer, it mainly just shows the order).

Step-by-step explanation:

1. -2 ¾

2. -3 ⅕

3. 0.75

4. 1.5

5. 6.8

7 0

3 years ago

Use simpson's rule with n = 10 to approximate the area of the surface obtained by rotating the curve about the x-axis. compare y

Lubov Fominskaja [6]

y = ln x , 1 <= x <= 3, about x axis and n = 10, dy/dx = 1/ x

S = (b a) ∫ 2π y √( 1 + (dy/dx) ^2) dx

so our f(x) is 2π y √( 1 + (dy/dx) ^2)

(b - a) / n = / 3 = (3-1) / 30 = 1/15

x0 = 1 , x1 = 1.2, x2 = 1.4, x3 = 1.6 ....... x(10) = 3

So we have , using Simpsons rule:-

S10 = (1/15) ( f(x0) + 4 f(x1) + 2 f)x2) +.... + f(x10) )

= (1/15) f(1) + f(3) + 4(f(1.2) + f(1.6) + f(2) + f(2.4) + f(2.8)) + 2(f(1.4) + f(1.8) + f(2.2) + f(2.6) )

( Note f(1) = 2 * π * ln 1 * √(1 + (1/1)^2) = 0 and f(3) = 2π ln3√(1+(1/3^2) = 7,276)

so we have S(10)

= 1/15 ( 0 + 7.2761738 + 4(1.4911851 +

5 0

4 years ago

0.0236 correct to 2 significant figure is

Oliga [24]

My key can’t perform this but I can solve it on a sheet...
So here I really hopes this helps

7 0

3 years ago

3 letters without replacement 4 letters A B C D how many ways can this be done if the order of the choices matters

Veseljchak [2.6K]

Answer:

Since the order of choice matters, we will permute the values. a bit more explanation for this:

If the order of choice did NOT matter, ABC and BCA will be counted as one since order of choice does NOT matter

Since order of choice does matter, ABC , BCA and CAB are all different possibilities for the arrangement of the same 3 letters

Since we have 3 slots:

___ ___ ___

Now, for the first slot. You can out either one if the 4 alphabets in the first slot since no slot has been used as of now

So:

_4_ ___ ___

**Keep in mind that the 4 is the possible number of values this slot can have**

Now that one slot has been used, one of the 4 alphabets has been used and since we are not allowed to repeat the same alphabets, we are left with 3 more alphabets

we can put any one of the 3 alphabets in this second slot, Hence:

_4_ _3_ ___

Now that 2 of the 4 alphabets have been used, we are left with only 2 alphabets, so there are only 2 possible alphabets for slot 3

Therefore:

_4_ _3_ _2_

Now that we know the possible alphabets for all 3 slots, we will multiply them with each other to get the total possible number of 3 - alphabet words we can make with 4 alphabets

Total possible words = 4 * 3 * 2

Total possible words = 24

We could've used the formula for Permutation as well

8 0

3 years ago

Can you help me solve this question? ​

Can you help me solve this question?