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guapka [62]
3 years ago
13

Please Answer this ddddd

Chemistry
1 answer:
deff fn [24]3 years ago
8 0

Answer:

I will answer it as C

Explanation:

6

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Agata [3.3K]
The answer is 20 centimeters
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4 years ago
What percent of an original sample remains after 3 half-lives? After 5 half-lives?
Salsk061 [2.6K]

Answer:

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7 0
4 years ago
When a metal was exposed to light at a frequency of 4.07× 1015 s–1, electrons were emitted with a kinetic energy of 3.30× 10–19
Licemer1 [7]

Answer :  The maximum number of electrons released = 1.432\times 10^{12}electrons

Explanation : Given,

Frequency = 4.07\times 10^{15}s^{-1}

Kinetic energy = 3.30\times 10^{-19}J

Total energy = 3.39\times 10^{-7}J

First we have to calculate the work function of the metal.

Formula used :

K.E=h\nu -w

where,

K.E = kinetic energy

h = Planck's constant = 6.626\times 10^{-34}J/s

\nu = frequency

w = work function

Now put all the given values in this formula, we get the work function of the metal.

3.30\times 10^{-19}J=(6.626\times 10^{-34}J/s\times 4.07\times 10^{15}s^{-1})-w

By rearranging the terms, we get

w=2.367\times 10^{-18}J

Therefore, the works function of the metal is, 2.367\times 10^{-18}J

Now we have to calculate the maximum number of electrons released.

The maximum number of electrons released = \frac{\text{ Total energy}}{\text{ work function}}

The maximum number of electrons released = \frac{3.39\times 10^{-7}J}{2.367\times 10^{-19}J}=1.432\times 10^{12}electrons

Therefore, the maximum number of electrons released is 1.432\times 10^{12}electrons

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3 years ago
Examine the picture below and read the description.
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3 years ago
ANSWER ASAP! PLEASE!
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Evaporation and straining.and idk the other two

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