Answer:
The answer to your question is the letter d.
Explanation:
Data
Zn + HCl ⇒ ZnCl₂ + H₂
- Calculate the Oxidation number of reactants and products
Zn⁰ + H⁺¹Cl⁻¹ ⇒ Zn⁺²Cl₂⁻¹ + H₂⁰
- Determine which elements changed their oxidation numbers
Zn⁰ ⇒ Zn⁺² Zn lost 2e⁻
2H⁺¹ ⇒ H₂⁰ H won 2 e⁻
-Interchange the electrons lost and won
2( Zn⁰ ⇒ Zn⁺²)
2(2H⁺¹ ⇒ H₂⁰)
-Simplify
2Zn⁰ ⇒ 2Zn⁺²
4H⁺¹ ⇒ 2H₂⁰
-Substitute the coefficient in the equation
2Zn + 4HCl ⇒ 2ZnCl₂ + 2H₂
Reactant Element Product
2 Zn 2
4 H 4
4 Cl 4
- Now the reaction is balanced
Answer:
2.103 J/C
Explanation:
Quantity of heat = Heat Capacity * Temperature change
Heat Capacity = Quantity of heat / Temperature Change
Heat Capacity = 61/29
Heat Capacity = 2.103 J/C
Answer: Extracellular [Ca2+]
Explanation:
The sensitivity and density of the alpha receptors serve to <em>enhance the response to the release of</em> <em>norepinephrine (NE)</em> . However, they do not exert a strong influence as the concentration of calcium ions on the amount of <em>norepinephrine (NE)</em> released by sympathic nerve terminals.
The release of neurotransmitters depends more on either an external or internal stimulus.This results in an action potential which on reaching a nerve terminal, results in the opening of Ca²⁺ channels in the neuronal membrane. Because the extracellular concentration of Ca²⁺ is greater than the intracellular Ca²⁺ concentration, Ca²⁺ flows into the nerve terminal. This triggers a series of events that cause the vesicles containing <em>norepinephrine (NE)</em> to fuse with the plasma membrane and release <em>norepinephrine (NE)</em> into the synapse. The higher the action potential, the higher the Ca²⁺ flow into the terminals resulting in higher amount of <em>norepinephrine (NE)</em> into the synapse, and vice versa.
Catechol-O-methyltransferase (COMT) is one of several enzymes that degrade catecholamines such as dopamine, epinephrine, and norepinephrine. It serves a regulatory purpose to lower the concentration of norepinephrine upon its release from nerve terminals.