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3 years ago

Please help!!!!!!!!!!

Mathematics

2 answers:

grigory [225]3 years ago

6 0

Itsss y=-3 ur welcomm

avanturin [10]3 years ago

3 0

Here’s the answer and work

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Gragh the image of the figure after a dilation with a scale factor of 1/4 centered at (5, -5) please help

svetoff [14.1K]

Answer:

See attached diagram

Step-by-step explanation:

Triangle ABC has vertices A(9,3), B(-7,-5) and C(-3,7).

The dilation with a scale factor of 1/4 centered at (5, -5) has the rule

$(x,y)\rightarrow \left(\dfrac{1}{4}x+\dfrac{15}{4},\dfrac{1}{4}y-\dfrac{15}{4}\right)$

Then

$A(9,3)\rightarrow A'\left(\dfrac{1}{4}\cdot 9+\dfrac{15}{4},\dfrac{1}{4}\cdot 3-\dfrac{15}{4}\right)=A'(6,-3);$

$B(-7,-5)\rightarrow B'\left(\dfrac{1}{4}\cdot (-7)+\dfrac{15}{4},\dfrac{1}{4}\cdot (-5)-\dfrac{15}{4}\right)=B'(2,-5);$

$C(-3,7)\rightarrow C'\left(\dfrac{1}{4}\cdot (-3)+\dfrac{15}{4},\dfrac{1}{4}\cdot 7-\dfrac{15}{4}\right)=C'(3,-2).$

6 0

3 years ago

Find the solution for the system of the equation c=-t+2 and c=-4t-4

romanna [79]

Answer:it’s a I think

Step-by-step explanation:

7 0

3 years ago

A garden table and a bench cost $589 combined. The garden table costs $61 less than the bench. What is the cost of the bench?

Paul [167]

Answer:

The bench costs $350

Step-by-step explanation:

et the cost of the bench = x

the cost of the garden table = x + 94

x + (x + 94) = 794

2x + 94 = 794

2x = 700

x = 350

The bench costs $350 and the garden table costs 350 + 94 = $444

7 0

3 years ago

The mother's age is 8 times her son's age. After 6 years, the age of the mother will be 9/2 times her son's age. The present age

Yakvenalex [24]

Answer:

son = 6 mother = 48

Step-by-step explanation:

Mother = m

son = s

m = 8s

m+6 = 9/2 * (s+6)

2(8s + 6) = 9(s +6)

16s + 12 = 9s + 54

16s - 9s = 54 - 12

7s = 42

s = 42/7 = 6 years old

so the mother is 8s = 8*6= 48 years old

4 0

3 years ago

Read 2 more answers

How to evaluate the limit

anzhelika [568]

$\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}$

Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

$\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5$

4 0

3 years ago