<span>If the grasses on a 100-hectare area of grassland grow at an average rate of 1 cm/day, the average volume of grass that is added to the grassland each day is 10,000 m3
</span><span>If the density of the grasses that grow in the grassland average 400 kg/m3, the NPP is approximately 4000 g/m2/day or 1460000 g/m2/year
Equations:
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100 hectare (x) 10,000 m2/hectare = 1(x)106 m2 (x) 0.01 m/day =</span></span>
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10,000 m3/day (x) 400 kg/m3 (x) 1000 g/1 kg = 4 (x) 109 g/day / 1 (x) 106 m2 =</span></span>
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4000 g/m2<span>/day (x) 365 day/year = </span>
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1. A
2.B
3.Y
so this is. Tricky so it's a
Answer:it’s the Truman Doctrine
Explanation:
Answer:
The correct answer is the Mean is greater than the median value if X.
Explanation:
Solution
From the question given, we will find out which is greater between the mean and median
Now,
The median value of X is less than the mean.
For a right skewed distribution the mean is greater than a median. it can be seen that the distribution the distribution of X is right positively/skewed/ or X has a longer right tail.
Note: Kindly find an attached copy of the complete question given.
I solved just a part of the question given here.