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3 years ago

Rate my bestie 1-10 be honest

Mathematics

2 answers:

BARSIC [14]3 years ago

7 0

Answer:

1000000000000000000000000000000000000000000000000000000000000000000000000

And yes I'm being honest! She is sooo pretty!!!!!!!!

Step-by-step explanation:

aleksklad [387]3 years ago

4 0

Answer:

7.5/10

Step-by-step explanation:

Her features are pretty but I think she will look better without the filter LOL

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Write a quadratic function in standard form with axis of symmetry x=-5 and y -intercept 3 .

Bezzdna [24]

Answer:

follow the statement below

Step-by-step explanation:

The question you presented here has multiple (un-limited) solutions unless you have another condition to solve for a single solution.

Equation: y = ax² + bx + c

y intercept (0 , 3): c = 3

axis of symmetry x=-5, therefore a corresponding point (-10,3) on the curve

3 = a*(-10)² + b*(-10) + 3

100a - 10b = 0

b = 10a .... any pair like a=0.5 b=5; a=1 b=10 0r a=2 b=20 ..... all fit the function

y = 0.5x² + 5x +3

y = x² + 10x + 3

y = 2x² + 20x +3

........................

8 0

3 years ago

A parabolà can be drawn given a focus of (7,9) and a

NeTakaya

from the provided focus point and directrix, we can see that the focus point is above the directrix, meaning is a vertical parabola and is opening upwards, thus the squared variable will be the "x".

keeping in mind the vertex is half-way between these two fellows, Check the picture below.

$\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill$

$\bf \begin{cases} h = 7\\ k = 7\\ p = 2 \end{cases}\implies 4(2)(y-7)=(x-7)^2\implies 8(y-7)=(x-7)^2 \\\\\\ y-7=\cfrac{1}{8}(x-7)^2\implies \boxed{y=\cfrac{1}{8}(x-7)^2+7}$

6 0

4 years ago

MODELING REAL LIFE A baseball is thrown up in the air. The table shows the heights $y$ (in feet) of the baseball after $x$ secon

nikklg [1K]

The equation for the path of the ball can be measured using a regression model calculator which produced the quadratic model ;

y(x) = - 16x² + 36x + 4
Height at x = 1.7 = 18.89 feets

<u>The table given</u> :

Time, x : __0.5 ___ 1 ____ 1.5 ____ 2

Height, y _ 18 ____22 ___ 24 ____ 12

<u>Using </u><u>technology</u><u> such as a </u><u>quadratic regression</u><u> calculator or </u><u>excel</u> ;

The quadratic regression model obtained is :

y(x) = - 16x² + 36x + 4

<u>The </u><u>height after, 1.7 seconds</u><u>, x = 1.7 can be calculated thus</u> :

Put x = 1.7 in the equation :

y(1.7) = - 16(1.7)² + 36(1.7) + 4
y = 18.89 feets

Therefore, the height of the baseball after 1.7 seconds will be 18.89 feets.

Learn more : brainly.com/question/22939512

5 0

2 years ago

Liam says that the graph of the function between x=1 and x=3 is non linear and increasing . What error could he have made in ana

____ [38]

I would say that (d) is the correct answer because the section between x=4 and x=6 is not linear but exponential but it is still increasing. The section between x=1 and x=3 however is linear and therefore his answer is incorrect.

7 0

4 years ago

A 0. 0427 kg racquetball is moving 22. 3 m/s when it strikes a stationary box. The ball bounces back at 11. 5 m/s, while the box

andreyandreev [35.5K]

To solve the question we must know about the conservation of momentum.

<h2>Conservation of Momentum</h2>

According to the law of conservation of momentum, when two bodies collide with each other then their momentum is conserved if no external force acts on the system. therefore, the combined momentum of the two objects before collision will be equal to the combined momentum of the two objects after the collision.

the momentum of the two objects before the collision

= momentum of the two objects after the collision

The mass of the box is 0.30141 kg.

<h2>Explanation</h2>

Given to us