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3 years ago

How to solve y = 8x - 9

Mathematics

2 answers:

SIZIF [17.4K]3 years ago

8 0

Answer:

what are you looking for? the value of y or x? or do you need it graphed?

Step-by-step explanation:

Alex Ar [27]3 years ago

6 0

Answer:

-72

Step-by-step explanation:

The answer is -72 because 8 * -9 = -72, I can't explain it to you any other way ;-;

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I don’t know how to type it out so here’s the picture.

jarptica [38.1K]

It’s the third one

i plugged two in for x to double check and it’s right

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3 years ago

When network cards are communicating, bits can occasionally be corrupted in transmission. Engineers have de- termined that the n

ycow [4]

Answer:

a) 11.40% probability of 5 bits being in error during the transmission of 1 kb

b) 11.60% probability of 8 bits being in error during the transmission of 2 kb

c) 0.01% probability of no error bits in 3kb

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the giveninterval.

Poisson distribution with mean of 3.2 bits/kb (per kilobyte).

This means that $\mu = 3.2kb$ , in which kb is the number of kilobytes.

(a) What is the probability of 5 bits being in error during the transmission of 1 kb?

This is P(X = 5) when $\mu = 3.2$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 5) = \frac{e^{-3.2}*3.2^{5}}{(5)!} = 0.1140$

11.40% probability of 5 bits being in error during the transmission of 1 kb

(b) What is the probability of 8 bits being in error during the transmission of 2 kb?

This is P(X = 8) when $\mu = 2*3.2 = 6.4$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 8) = \frac{e^{-6.4}*6.4^{8}}{(8)!} = 0.1160$

11.60% probability of 8 bits being in error during the transmission of 2 kb

(c) What is the probability of no error bits in 3kb?

This is P(X = 0) when $\mu = 3*3.2 = 9.6$

Then

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-9.6}*9.6^{0}}{(0)!} = 0.0001$

0.01% probability of no error bits in 3kb

7 0

3 years ago

A rental car costs $50 for one day plus an additional $0.25 per mile. What is the cost of renting a car for one day and driving

charle [14.2K]

The equation for this problem would be 50 + .25x, so if x is equal to 75, then the total would be $68.75

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4 years ago

Read 2 more answers

What is $240.267.40 increased by 147%

vladimir2022 [97]

Increasing by 147% means that we are at 100% right now and we need to get to 247%. That is because 100+147=247. It is pretty tricky in that way.

$240267.40 x 2.47 = $593460.48 approx.

answer: $593460.48 approx.

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4 years ago

You roll 2 dice. You can use a tree diagram to calculate the probability that the sum of the dice is an even number. true or fal

Oduvanchick [21]

The correct answer for the given statement above would be TRUE. It is true that you can use a tree diagram to calculate the probability that the sum of the dice is an even number. In math, a tree diagram is used to see all the possible outcomes of a certain event and its probability. A way that you can use a tree diagram for this is like this: list all possibilities from 1 to 6. For each of these, list all possibilities from 1 to 6. This gives you 36 branches at lower level. Hope this answer helps.

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3 years ago