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yan [13]
3 years ago
9

(rs) (4) = (r/s) (3) =

Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0

<em>(R/S) (3)= 2 </em>is your answer.

Llana [10]3 years ago
6 0
I think first 8
Second 2
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A computer hard drive contains a circular disk with diameter 2.5 inches and spins at a rate of 7200 RPM (revolutions per minute)
PIT_PIT [208]

Now to solve this problem, all we have to remember is the formula for calculating the linear speed given the radial speed, that is:

v = r w

where,

v = is the linear velocity or linear speed

r = is the radius of the circular disk = (1 / 2) diameter = (1/ 2) (2.5 inches) = 1.25 inches

w = is the radial velocity (must be in rad per time) = 7200 rev per minute

 

Calculating for v:

v = 1.25 inches (7200 rev per minute) (2 π rad / 1 rev)

v = 56,548.67 inches / minute

 

Converting to miles per hour:

v = 56,548.67 inches / minute (1 mile / 63360 inches) (60 min / hour)

<span>v = 53.55 mile / hour</span>

4 0
3 years ago
1. Use the Distributive Property to simplify the expression.
klemol [59]

1 the answer is c-4

2 ?

3 Nothing further can be done with this topic

4 Remove parentheses.  2 x−4

5 6(b - p)

6 Nothing further can be done with this topic

7 98

7 0
4 years ago
Question 7<br>(05.02 LC)<br>What is the measure of angle x? (1 point)​
attashe74 [19]

Answer:

43

Step-by-step explanation:

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4 0
4 years ago
Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"
Bas_tet [7]

The question is:

Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements.

a. Jerry does not have an Internet connection.

b. Rachel has not chatted over the Internet with Chelsea.

c. Jan and Sharon have never chatted over the Internet.

d. No one in the class has chatted with Bob.

e. Sanjay has chatted with everyone except Joseph.

f. Someone in your class does not have an Internet connection.

g. Not everyone in your class has an Internet connection.

h. Exactly one student in your class has an internet connection.

i. Everyone except one student in your class has an Internet connection.

j. Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class.

k. Someone in your class has an Internet connection but has not chatted with anyone else in your class.

l. There are two students in your class who have not chatted with each other over the Internet.

m. There is a student in your class who has chatted with everyone in your class over the Internet.

n. There are at least two students in your class who have not chatted with the same person in your class.

o. There are two students in the class who between them have chatted with everyone else in the class.

Step-by-step explanation:

Note that: Because the arguments are variables, we write

Ix = I(x)

Cxy = C(x,y)

a. Jerry does not have an Internet connection.

~I(Jerry).

b. Rachel has not chatted over the internet with Chelsea.

~C(Rachel,Chelsea).

c. Jan and Sharon have never chatted over the internet.

~C(Jan,Sharon).

d. No one in the class has chatted with Bob.

~∃x C(x, Bob).

e. Sanjay has chatted with everyone except Joseph.

∀y (y ≠ Joseph → C(Sanjay, y)).

f. Someone in your class does not have an internet connection.

∃x ~Ix.

g. Not everyone in your class has an internet connection.

~∀x Ix.

h. Exactly one student in your class has an internet connection.

∃x (Ix ∧ ∀y (Iy → y = x)).

i. Everyone except one student in your class has an internet connection. This means exactly one student does not have a connection.

∃x (~Ix∧ ∀y (Iy → y = x)).

j. Everyone in your class with an internet connection has chatted over the internet with at least one other student in your class.

∀x (Ix → ∃y (Cxy ∧ x ≠ y)).

Assuming nobody can chat with him or herself, then

∀x (Ix → ∃y (Cxy))

k. Someone in your class has an internet connection but has not chatted with anyone else in your class.

∃x (Ix ∧ ∀y ~Cxy).

l. There are two students in your class who have not chatted with each other over the internet.

∃x ∃y (x ≠ y∧~Cxy).

m. There is a student in your class who has chatted with everyone in your class over the internet.

∃x ∀y Cxy.

n. There are at least two students in your class who have not chatted with the same person in your class. ∃x ∃y (x ≠ y ∧ ∃z (~Cxz ∧ ~Cyz)).

o. There are two students in the class who between them have chatted with everyone else in the class.

∃x ∃y (x ≠ y ∧ ∀z (Cxz ∨ Cyz)).

5 0
4 years ago
Forty randomly selected students were asked the number of pairs of sneakers they owned. Let X = the number of pairs of sneakers
eimsori [14]

The mean of sample x is 5.83

The standard deviation is 5.63

<h3>What is standard deviation?</h3>

A standard deviation (or σ) is a measure of how dispersed the data is in relation to the mean. Low standard deviation means data are clustered around the mean, and high standard deviation indicates data are more spread out.

Given:

Frequency:  2 2 4 13 13 1

If x is the pair of sneakers owned of the frequency,

mean = 2+2+4+13+13+1/5

= 35/6

= 5.83

The  standard deviation is equal to 5.63.

Learn more about this concept here:

brainly.com/question/18119796

#SPJ1

8 0
3 years ago
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