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yan [13]
3 years ago
9

(rs) (4) = (r/s) (3) =

Mathematics
2 answers:
liubo4ka [24]3 years ago
8 0

<em>(R/S) (3)= 2 </em>is your answer.

Llana [10]3 years ago
6 0
I think first 8
Second 2
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Scott bought a backpack for $35.99 at Walmart. He needed to pay a 10% tax. How much did the backpack cost in all?
stellarik [79]
$35.99 x .10=3.599
$35.99 + 3.60=$39.59
8 0
4 years ago
Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that
Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is P(x_1 + x_2 \ge 2 )= 0.5940

Step-by-step explanation:

From the question we are told that

     The rate at which fire breaks out every 10 years is  \lambda  =  1

  Generally the probability distribution function for Poisson distribution is mathematically represented as

               P(x) =  \frac{\lambda^x}{ k! } * e^{-\lambda}

Here x represent the number of state which is  2 i.e x_1 \ \ and \ \ x_2

Generally  the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

          P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 + x_2 \le 1 )

=>        P(x_1 + x_2 \ge 2 ) =  1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]

=>        P(x_1 + x_2 \ge 2 ) =  1 - [ P(x_1  = 0 ,  x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]

=>  P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)

=>    P(x_1 + x_2 \ge 2 ) =  1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}

=>   P(x_1 + x_2 \ge 2 )= 1- [[0.3678  * 0.3679] + [0.3678  * 0.3679] + [0.3678  * 0.3679]  ]

P(x_1 + x_2 \ge 2 )= 0.5940

               

3 0
3 years ago
What is the value of 3 in the figure shown below?
NeX [460]

9514 1404 393

Answer:

  32

Step-by-step explanation:

Angle E is congruent to angle C, so is the value required to make the sum of angles in triangle ABC be 180°.

  ∠E = 180° -118° -30° = 32°

The value of x is 32.

7 0
3 years ago
How old is Michael now?
anyanavicka [17]
Which Michael?? There are many many many Michaels in the world
3 0
3 years ago
What is the absolute mean deviation of this data?<br> 1, 2, 3, 3, 4,5, 6, 8
Harlamova29_29 [7]

Answer:

4/1/7 ( 4 and 1 over 7)

Step-by-step explanation:

First add all the numbers

1+2+3+4+5+6+8= 29

Finally you divide the total by counting the numbers which you have add up

29÷7

= 4/1/7 ( 4 and 1 over 7)

Mark me as the brainiest answer

7 0
3 years ago
Read 2 more answers
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