I need someone to check my work..
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Answer:
the graph is in the attachment.
the coordinates of the centroid : (2/3,2/3)
Step-by-step explanation:
- y=0 represents x-axis ( you can easily mark it on the graph)
- now draw x=1 line.( It is a line parallel to y axis and passing through the point (1,0) )
- y=2x is a line which passes through origin and has a slope "2"
by using these sketch the region.
I have uploaded the region bounded in the attachment. You may refer it. The region shaded with grey is the required region.
- to find centroid:
it can be easily identified that the formed region is a triangle
- the coordinates of three vertices of the triangle are
(1,2) , (0,0) , (1,0)
( See the graph. the three intersection points of the lines are the three vertices of the triangle)
- for general FORMULA, let the coordinates of three vertices of a triangle PQR be P(a,b) , Q(c,d) , R(e,f)
- then the coordinates of the centroid( let say , G) of the triangle is given by
G =
- therefore , the exact coordinates of the centroid =
this point is marked as G in the graph uploaded.
