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3 years ago

6

Answers for the 2 boxes please

1 answer:

pochemuha3 years ago

6 0

(-3,-6) this is the answer you can also double check by plugging it into a calculator

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What is the value of the expression? 18 - 2 x (4 + 3)

Arturiano [62]

Answer:

=−14x+18

Step-by-step explanation:

happy to help ya :)

7 0

3 years ago

Read 2 more answers

one each day dariene write in her personal diary and records whether the sun isshining or not when she looked back tough her dia

Svetradugi [14.3K]

Im guessing ten or some sort of factor of ten

7 0

4 years ago

Read 2 more answers

In the coordinate plane, the point A, 4− 2 is translated to the point A′, 1− 5. Under the same translation, the points B, 7− 4 a

Inga [223]

Answer:

The coordinates of B' and C' are $B'(x,y) = (4, -7)$ and $C'(x,y) = (-1, -8)$ , respectively.

Step-by-step explanation:

From the Linear Algebra, we define the translation of a given point as:

$O'(x,y) = O(x,y) + T(x,y)$ (1)

Where:

$O(x,y)$ - Original point, dimensionless.

$T(x,y)$ - Translation vector, dimensionless.

$O'(x,y)$ - Translated point, dimensionless.

If we know that $A'(x,y) = (1, -5)$ and $A(x,y) = (4,-2)$ , then the translation vector is:

$T(x,y) = A'(x,y)-A(x,y)$ (2)

$T(x,y) = (1,-5)-(4,-2)$

$T(x,y) = (-3,-3)$

If we know that $B(x,y) = (7,-4)$ , $C(x,y) = (2,-5)$ and $T(x,y) = (-3,-3)$ , then the translated points are, respectively:

$B'(x,y) = B(x,y)+T(x,y)$ (3)

$B'(x,y) = (7,-4) +(-3,-3)$

$B'(x,y) = (4, -7)$

$C'(x,y) = C(x,y) +T(x,y)$

$C'(x,y) = (2,-5) + (-3,-3)$

$C'(x,y) = (-1, -8)$

The coordinates of B' and C' are $B'(x,y) = (4, -7)$ and $C'(x,y) = (-1, -8)$ , respectively.

5 0

3 years ago

Multiply sixth of sixty six by a half of ten <br><br> Show step by step method

zimovet [89]

The answer is 55
$(66 \times \frac{1}{6}) \times ( 10 \times \frac{1}{2} ) = \frac{66}{6} \times \frac{10}{2} \\ = 11 \times 5 = 55$

good luck

3 0

3 years ago

Use the diagram to complete the statement.

Dima020 [189]

Answer:

∠FJH ≅ ∠BJA

Step-by-step explanation:

From the image we can see that the only congruent relation ∠FJH has is with ∠BJA which is due to these angles being vertically opposite

So, ∠FJH and ∠BJA are vertically opposite and hence, congruent. We can say that ∠FJH ≅ ∠BJA

4 0

3 years ago