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Olegator [25]
3 years ago
10

Find the equation of a line through the coordinate (3,−2) and parallel to the line represented by y=12x−2.

Mathematics
1 answer:
denis-greek [22]3 years ago
7 0

Answer:

Step-by-step explanation:

y + 2 = 12(x - 3)

y + 2 = 12x - 36

y =12x - 38

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Step-by-step explanation:

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2 years ago
Help, Help, Please
Lesechka [4]

Answer:

θ = \frac{\pi }{3} (60° )

Step-by-step explanation:

Using the identity

sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x

Given

cos²θ - sin²θ = 2 - 5cosθ

cos²θ - (1 - cos²θ) = 2 - 5cosθ

cos²θ - 1 + cos²θ = 2 - 5cosθ

2cos²θ - 1 = 2 - 5cosθ ( subtract 2 - 5cosθ from both sides )

2cos²θ + 5cosθ - 3 = 0 ← in standard form

(cosθ + 3)(2cosθ - 1) = 0 ← in factored form

Equate each factor to zero and solve for θ

cosθ + 3 = 0

cosθ = - 3 ← not possible as - 1 ≤ cosθ  ≤ 1

2cosθ - 1 = 0

cosθ = \frac{1}{2} , so

θ = cos^{-1} (\frac{1}{2} ) = \frac{\pi }{3} ( or 60° )

8 0
2 years ago
Read 2 more answers
13% of $99.99 =<br> $26.00<br> O $25.98<br> O $13.00<br> O $12.99
vova2212 [387]

Answer:

12.99 or 13 rounded

Step-by-step explanation:

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8 0
2 years ago
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