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3 years ago

Use the table to write a proportion.

Mathematics

2 answers:

Mademuasel [1]3 years ago

7 0

6 penalties/8 penalties
16 min/21.3

Vikentia [17]3 years ago

6 0

Answer:

8888888

Step-by-step explanation:

Yeah i dont know how to solve this, the answer down below isnt right, so I'm done for! :)

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What is the slope between 8,-7 and 5,-3

Citrus2011 [14]

-4/3 I believe is your answer.

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3 years ago

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8. Given that DAB and DCB are right angles and BDC = 55°, what is m CAD?

Artyom0805 [142]

Answer:

Step-by-step explanation:

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3 years ago

The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is three time

Orlov [11]

Answer:

x = 45°, y = 53°, z = 82°

Step-by-step explanation:

x is the first angle, y is the second, and z is the third.

The sum of the second and third, which is denoted by y + z, is 3 times the measure of the first, which is just x. So, we have:

y + z = 3 * x

Additionally, the third angle, z, is 29 more than the second, y, so:

z = 29 + y

We also know that the sum of the three is 180, so:

x + y + z = 180

Let's substitute y + z in the last equation with 3 * x:

x + y + z = 180

x + 3x = 180

4x = 180

x = 45

Now, we know that y + z = 3 * 45 = 135. We also know that z = 29 + y, so substitute 29 + y in for z in y + z = 135:

y + z = 135

y + (29 + y) = 135

2y + 29 = 135

2y = 106

y = 53

Finally, use this value of y to solve for z:

z = 29 + y

z = 29 + 53 = 82

Thus, the angles are x = 45°, y = 53°, and z = 82°.

<em>~ an aesthetics lover</em>

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3 years ago

.) The function g is related to one of the parent functions g(x) = |x − 1| + 5 a.) Identify the parent function f. b.) Use funct

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Answer:

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3 years ago

In 1990, the average duration of long-distance telephone calls originating in one town was A long-distance telephone company wan

Ratling [72]

Answer:

The null hypothesis is $H_0: \mu = X$

The alternate hypothesis is $H_1: \mu \neq X$

Step-by-step explanation:

Mean of X in 1990, test if the mean duration has changed:

At the null hypothesis, we test if the mean duration is still X, that is:

$H_0: \mu = X$

At the alternate hypothesis, we test if the mean duration has the changed, that is, if it is different of X. So

$H_1: \mu \neq X$

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3 years ago