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NeTakaya
3 years ago
12

Heeeeeeelppppppppppp

Mathematics
1 answer:
sleet_krkn [62]3 years ago
6 0

Step-by-step explanation:

I'll help you darling

a. B

b. 2.6 + x = 10.4

c. x = 10.4 - 2.6

= 7.8

d. This is to say before mia added the 2.6 litres of what the pitcher contained 7.8 litres of water already

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Not troll! Please help, will give brainliest! Explain your answer and how you got it.
Mkey [24]

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33  7/9 or 304/9

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Write a word problem that would require you to use 5621÷23
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8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=5x-8%3D4x-5" id="TexFormula1" title="5x-8=4x-5" alt="5x-8=4x-5" align="absmiddle" class="latex
Ilia_Sergeevich [38]

Answer:

Solution given:

5x-8=4x-5

or

5x-4x=8-5

x=3

<u>x</u><u>=</u><u>3</u>

8 0
3 years ago
Read 2 more answers
A metallurgist has an alloy with 5​% titanium and an alloy with 25​% titanium. He needs 100 grams of an alloy with 13​% titanium
Nimfa-mama [501]
So... the alloy with 5% titanium is ...some  alloy :), so is a mixed metal and among its mix it has 5% of titanium, it has other metals, but only 5% is titanium.

that means that if the amount of it is say "x", then the amount of titanium in it will be 5% or (5/100) * x, or 0.05x.

now, the 25% titanium, is the same issue, if say a quantity of "y" will only have 25% of titanium, regardless of other metals, so in "y" there is 25% or (25/100) * y, or 0.25y.

so, we need a mixture that yields only a 13% alloy, or 13/100, and will be 100 grams, so the amount of titanium in it will then be (13/100) * 100 or 13.

\bf \begin{array}{lccclll}&#10;&\stackrel{grams}{amount}&\stackrel{\%}{quantity}&\stackrel{concentrated}{quantity}\\&#10;\textit{5\% alloy}&x&0.05&0.05x\\&#10;\textit{25\% alloy}&y&0.25&0.25y\\&#10;------&------&------&------\\&#10;mixture&100&0.13&13&#10;\end{array}&#10;\\\\\\&#10;\begin{cases}&#10;x+y=100\implies \boxed{y}=100-x\\&#10;0.05x+0.25y=13\\&#10;----------\\&#10;0.05x+0.25\left( \boxed{100-x} \right)=13&#10;\end{cases}&#10;\\\\\\&#10;0.05x-0.25x+25=13\implies -0.20x=-12\implies x=\cfrac{-12}{=0.20}&#10;\\\\\\&#10;x=\stackrel{grams}{60}

how much of the 25% alloy will be needed?  well, y = 100 - x.
4 0
3 years ago
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