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harina [27]
3 years ago
13

What is the slope of this line is it 0 or 1 or 2 or 3 or undefined

Mathematics
2 answers:
Naily [24]3 years ago
8 0

Answer:

1

Step-by-step explanation:

algol [13]3 years ago
3 0

Answer:

The answer is 1

Step-by-step explanation:

Using the rise over run strategy, you can get this answer by...

1. Look at the line and graph 2 points. ( 1 , 1 ) & ( 2 , 2 ).

2. Do the rise over run thing. ( how am I going to get from 1 point to the other.)

You get to it by rising 1 and running 1. The pattern is self explanatory.

3. Divide rise over run and the quotient is your answer

1 divided by 1 is 1.

Hope this Helps and Pls mark Brainliest.

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Which line segments in the diagram below are parallel?
AveGali [126]
The answer is B due to the corresponding 130
8 0
2 years ago
PLEZ HELP ASAP
lisov135 [29]

Answer:

a median

b center

Step-by-step explanation:

The middle value of a set of numbers is the median

The mean is the average value and the range is the largest minus the smallest.

This value is  a measure of the center ( or a measure of the middle)

The range is a measure of the spread

8 0
3 years ago
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Solve for t <br><br> t/5/12=-3/10
natka813 [3]
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6 0
3 years ago
Paying 20$ cashapp if you get this correct
Ilia_Sergeevich [38]

Answer:

148⁰

Step-by-step explanation:

M< EDF = M< DFE (because the two angles are equal because the triangle has two equal sides)

2x + 8 = 3x + 4

8 – 4 = 3x - 2x

4=x or x=4

So M< EDF= 2x4+8 = 16⁰  

So M< EDF + M< DFE= 32⁰

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3 0
3 years ago
5. Solve using any method.<br> y = -x + 8<br> y=x+4
vlada-n [284]

Answer:

<h2>x = 2, y = 6 → (2, 6)</h2>

Step-by-step explanation:

\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}

7 0
3 years ago
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