3 years ago

Write the equation of the perpendicular line with the points (-9,2) with the equation 3x-y=12

Mathematics

1 answer:

DedPeter [7]3 years ago

6 0

Answer:

y=-1/3x-1

Step-by-step explanation:

Perpendicular lines have slope that are opposite sign and reciprocals

3x-y=12 has a slope of 3, therefore perpendicular line must have slope of -1/3

2=-9(-1/3)+b

2=3+b

b=-1

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∠A and \angle B∠B are vertical angles. If m\angle A=(6x-11)^{\circ}∠A=(6x−11) ∘ and m\angle B=(5x+4)^{\circ}∠B=(5x+4) ∘ , then f

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Step-by-step explanation:

When two lines cross each other , then the opposite angles are known as vertical angles.

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Here, ∠A and ∠B are vertical angles.

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If $\angle A=(6x-11)^{\circ}$ and $\angle B=(5x+4)^{\circ}$

Then , $6x-11=5x+4$

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