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ira [324]
3 years ago
7

Help will mark brainliest

Mathematics
2 answers:
juin [17]3 years ago
7 0

Answer:

Yea it has to be 8

Step-by-step explanation:

Allisa [31]3 years ago
6 0
The answer is 8 .. hope this helps a lot :)
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Hayley borrowed $1,854 from her parents. She agreed to repay them in equal installments throughout the next 18 months. How much
Serggg [28]

Answer: $ 618

Step-by-step explanation:

Money borrowed =  $1,854

Total months taken to repay = 18  (Number of installments)

Money paid per month = \dfrac{\text{Money borrowed}}{\text{Number of installments}}

=\dfrac{1854}{18}=\$103

Now , money paid in 1 year = 12 x $ 103 =$ 1236     [1 year = 12 months ]

After a year , Haley still owe =  $1,854 -  $ 1236= $ 618

Hence, Haley still owe her parents $618 after a year .

7 0
3 years ago
The sum of a + b is an odd number if
Grace [21]

Answer:

a is an even number and b is an odd number

Step-by-step explanation:

if a is even and b is even then the sum would be even ex.10+6=16. I'd a and b are both odd the sum would be even ex. 13+9=22. one has to be odd and one has to be even for the sum to be odd ex. 5+4=9

8 0
3 years ago
(√2+√3) ^2<br>answer faaaaaaaaaaaaast<br>​
ad-work [718]

Answer:

2.5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Hcf and LCM of 391 and 236
mash [69]

Answer:

LCM = 92276

HCF = 1

Step-by-step explanation:

5 0
2 years ago
Can you help me with number 6? <br> Confused abit <br> Please
Sunny_sXe [5.5K]

You can see the three diagram attached. Each link is labeled with the probability: you have probability 1/6 that a six is rolled, and 5/6 that it is not rolled.


To answer the questions, find the path that brings you to the desired outcome, and multiply all the labels you meet.


First question:

To get three sixes, you have to choose the left path at each roll. The probability is always 1/6, so the answer is


\frac{1}{6} \times \frac{1}{6} \times \frac{1}{6} = \frac{1}{6^3}


Second question:

To get no sixes, you have to choose the right path at each roll. The probability is always 5/6, so the answer is


\frac{5}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^3}{6^3}


Third question:

To get exactly one six, it can either be the first, second or third roll.


In all cases, you have to choose the left path once and the right path twice: left-right-right mean that you get the six in the first roll, right-left-right means that you get the six in the second roll, right-right-left means that you get the six in the third roll.


In every case, the left turn has probability 1/6, and the right turn has probability 5/6. The probability of each combination is thus


\frac{1}{6} \times \frac{5}{6} \times \frac{5}{6} = \frac{5^2}{6^3}


And since there are three of these combinations, The answer is


3\frac{5^2}{6^3}


Fourth question:

Since the question suggests to use what we already achieved, let's do it: having at least one six is the complementary event of having no sixes at all. If an event has probability p, its complementary has probability 1-p. So, since the probability of no sixes is known, the probability of at least one six is


1 - \frac{5^3}{6^3}

4 0
3 years ago
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