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3 years ago

HELP me please.............

Mathematics

1 answer:

denis23 [38]3 years ago

5 0

Answer:

x+Y=0< dependent

x−Y=0 <dependent

x+Y=2< inconsistent

x−2Y=4x−Y=−1 < inconsistent

x−Y=−2Ta< independent

Step-by-step explanation:

I haven't learn these type of questions yet only freshman in high so tried to come up with the best answers with a lot of research

Hope this help

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A number less than two

murzikaleks [220]

Answer:

Step-by-step explanation:

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3 years ago

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How to solve burger barn has 46 2/3 pounds of ground beef. how many 1/3 pound burgers can be made using all the ground beef?

8_murik_8 [283]

(46 2/3) / (1/3) =
(140/3) / (1/3) =
140/3 * 3/1 =
420/3 =
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3 years ago

A population of 550 rabbits is increasing by 7.5% each year. In about how many years will the population be over 1000?

Dovator [93]

Answer:

D.) 15 years

Step-by-step explanation:

7.5% of 550 rabbits would be 41.25

if you are increasing till you get over 1,000

it would take 10.9 almost 11 years to get to 1,000

meaning it would be 15 years when your over 1,000 giving you 1,168.75

8 0

3 years ago

How do you solve and simplify 2/5+1/4+7/10=

Alchen [17]

Hello!

Answer: ⇒ 27/20

Step-by-step explanation:

$\frac{8}{20}+\frac{5}{20}+\frac{14}{20}$

Since the denominators are equal, then combine the fractions.

$\frac{8+5+14}{20}$

Add by the numbers.

$8+5+14=27$

$=\frac{27}{20}$

Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

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4 0

3 years ago

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The probability that a certain hockey team will win any given game is 0.3723 based on their 13 year win history of 385 wins out

Whitepunk [10]

Answer:

0.1505 = 15.05% probability that the hockey team wins 6 games in November

Step-by-step explanation:

For each game, there are only two possible outcomes. Either the team wins, or it does not. The probability of winning a game is independent of winning other games. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a certain hockey team will win any given game is 0.3723

So $p = 0.3723$

12 games in November

So $n = 12$

What is the probability that the hockey team wins 6 games in November?

This is $P(X = 6)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{12,6}.(0.3723)^{6}.(1-0.3723)^{6} = 0.1505$

0.1505 = 15.05% probability that the hockey team wins 6 games in November

4 0

3 years ago

HELP me please.............​

HELP me please.............