If someone wouldn’t mind answering the first question for me

2 ways to assign a value to a variable

Art [367]

Assigning values at run time
Assigning values as command line argument, before execution of the program

4 0

3 years ago

¿Cuales son las empresas mas exitosas que aún usan hoja de cálculo? porfa es urgentee

dem82 [27]

Answer:excel

Explanation:

6 0

2 years ago

Write a while loop that prints userNum divided by 2 (integer division) until reaching 1. Follow each number by a space.

Ksenya-84 [330]

Answer:

while(userNum>=1){

System.out.print(userNum/2+" ");

userNum--;

}

Explanation:

This is implemented in Java programming language. Below is a complete code which prompts a user for the number, receives and stores this number in the variable userNum.

import java.util.Scanner;

public class TestClock {

 public static void main(String[] args) {

 Scanner in = new Scanner (System.in);

 System.out.println("Enter the number");

 int userNum = in.nextInt();

 while(userNum>=1){

 System.out.print(userNum/2+" ");

 userNum--;

 }

}

The condition for the while statement is userNum>=1 and after each iteration we subtract 1 from the value of userNum until reaching 1 (Hence userNum>=1)

3 0

3 years ago

Write a program that reads the contents of the two files into two separate lists. The user should be able to enter a boy’s name,

insens350 [35]

Answer:

Check Explanation.

Explanation:

A programming language is used by engineers, technologists, scientists or someone that learnt about programming languages and they use these programming languages to give instructions to a system. There are many types for instance, c++, python, Java and many more.

So, the solution to the question above is given below;

#define the lists

boyNames=[]

girlNames=[]

#open the text file BoyNames.txt

with open('BoyNames.txt','r') as rd_b_fl:

boyNames=rd_b_fl.readlines()

boyNames=[name.strip().lower() for name in boyNames]

#open the text file GirlNames.txt

with open('GirlNames.txt','r') as rd_b_fl:

girlNames=rd_b_fl.readlines()

girlNames=[name.strip().lower() for name in girlNames]

#print the message to prompt for name

print('Enter a name to see if it is a popular girls or boys name.')

while True:

#prompt and read the name

name=input('\nEnter a name to check, or \"stop\" to stop: ').lower()

# if the input is stop, then exit from the program

if name=='stop':

break

# If the girl name exits in the file,then return 1

g_count=girlNames.count(name)

# if return value greater than 0, then print message

if g_count>0:

print(name.title()+" is a popular girls name and is ranked "

+str(girlNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular girls name")

## If the boy name exits in the file,then return 1

b_count=boyNames.count(name)

if b_count>0:

print(name.title()+" is a popular boys name and is ranked "

+str(boyNames.index(name)+1))

# if return value greater than 0, then print message

#"Not popular name"

else:

print(name.title()+" is not a popular boys name")

3 0

3 years ago

Input 3 positive integers from the terminal, determine if tlrey are valid sides of a triangle. If the sides do form a valid tria

butalik [34]

Answer:

In Python:

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

if side1>0 and side2>0 and side3>0:

if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

if side1 == side2 == side3:

print("Equilateral Triangle")

elif side1 == side2 or side1 == side3 or side2 == side3:

print("Isosceles Triangle")

else:

print("Scalene Triangle")

else:

print("Invalid Triangle")

else:

print("Invalid Triangle")

Explanation:

The next three lines get the input of the sides of the triangle

side1 = float(input("Side 1: "))

side2 = float(input("Side 2: "))

side3 = float(input("Side 3: "))

If all sides are positive

if side1>0 and side2>0 and side3>0:

Check if the sides are valid using the following condition

if side1+side2>=side3 and side2+side3>=side1 and side3+side1>=side2:

Check if the triangle is equilateral

if side1 == side2 == side3:

print("Equilateral Triangle")

Check if the triangle is isosceles

elif side1 == side2 or side1 == side3 or side2 == side3:

print("Isosceles Triangle")

Otherwise, it is scalene

else:

print("Scalene Triangle")

Print invalid, if the sides do not make a valid triangle

else:

print("Invalid Triangle")

Print invalid, if the any of the sides are negative

else:

print("Invalid Triangle")

4 0

3 years ago