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horsena [70]
3 years ago
12

Jay tosses two coins several times. The results are below.

Mathematics
1 answer:
ss7ja [257]3 years ago
4 0

Answer:

  • C. 3/5

Step-by-step explanation:

As per experiment, coins tossed 5 times and coins landed on different sides 3 times:

  • Toss 2: H;T, Toss 3: T;H, Toss 5: T;H

<u>This gives us the experimental probability of:</u>

  • 3 out of 5 or 3/5

Correct choice is C

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Consider the curve y=ln(3x-1).let p be the point on the curve where x=2.
liraira [26]
A. Yes you are correct that the gradient at any point is 3/(3x-1). However at point P it would be 3/(3*2-1)=2/5
b. The gradient of the normal would therefore be -5/2
We can use the general formula of an equation to get y-ln(5)=-5/2 (x-2)
Now multiply both sides by 2 to get:
2y-2ln(5)=-5x+10
Now when it crosses the x axis we know that y=0 therefore:
5x=10+2ln(5)
Therefore:
x=2+2/5 ln(5) when y=0
You could find an estimate of this number to be 2.64 (3sf) but this might not be sufficient

4 0
3 years ago
What is the measure of &lt; B ? help !!
mixer [17]

The choose (C) 60

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3 years ago
Write cos^4x as an equivalent expression that does not contain powers of trigonomretric functions greater than 1
SVETLANKA909090 [29]
cos^{4}x [/tex] = cos^{2}x.cos{2}x = (cos2x+1)(cos2x+1)/4

4 0
3 years ago
Which graph represents the function f(x) = (x – 3)2?
hjlf

Answer:

C) The third graph.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
If the diameter of a smaller circle is 7 km and the width of the circular path is 0.5 km, find the area of the path.
Strike441 [17]

We have been given that the diameter of a smaller circle is 7 km and the width of the circular path is 0.5 km. We are asked to find the area of the path.

The area of the path will be equal to area of larger circle minus area of smaller circle.

\text{Area of circle}=\pi r^2, where r represents radius of circle.

We know that radius is half the diameter, so radius of smaller circle would be \frac{7}{2}=3.5 km.

The radius of the larger circle will be radius of smaller circle plus width of the path that is 3.5+0.5=4 km.

\text{Area of circular path}=\pi (4)^2-\pi (3.5)^2

\text{Area of circular path}=16\pi-12.25\pi

\text{Area of circular path}=3.75\pi

\text{Area of circular path}=11.78097

\text{Area of circular path}\approx 11.8

Therefore, the area of the circular path is approximately 11.8 square km.

4 0
3 years ago
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