A. Yes you are correct that the gradient at any point is 3/(3x-1). However at point P it would be 3/(3*2-1)=2/5
b. The gradient of the normal would therefore be -5/2
We can use the general formula of an equation to get y-ln(5)=-5/2 (x-2)
Now multiply both sides by 2 to get:
2y-2ln(5)=-5x+10
Now when it crosses the x axis we know that y=0 therefore:
5x=10+2ln(5)
Therefore:
x=2+2/5 ln(5) when y=0
You could find an estimate of this number to be 2.64 (3sf) but this might not be sufficient
The choose (C) 60
The measure of the angles of a triangle is 180, and this triangle is equilateral, so 180/3=60, each angle is 60°
Answer:
C) The third graph.
Step-by-step explanation:
We have been given that the diameter of a smaller circle is 7 km and the width of the circular path is 0.5 km. We are asked to find the area of the path.
The area of the path will be equal to area of larger circle minus area of smaller circle.
, where r represents radius of circle.
We know that radius is half the diameter, so radius of smaller circle would be
km.
The radius of the larger circle will be radius of smaller circle plus width of the path that is
km.





Therefore, the area of the circular path is approximately 11.8 square km.