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bezimeni [28]
2 years ago
8

2x+5y=-11. -8x-5y=-11

Mathematics
2 answers:
elena-s [515]2 years ago
7 0
8x+5y-11=0 (That’s -8x5y=-1 simplified
MissTica2 years ago
3 0
2x+5y=-11 slope is -2/5, y- intercept is -11/5
-8x-5y=-11 slope is -8/5, y- intercept is 11/5
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Weiming receives a weekly pocket money of $28. If he decides to save 20% of it, find his saving in a year and spendings in a yea
Maru [420]

Welming's spending is $1164.8 and his savings is $291.2

<h3>How to determine the savings and the spending?</h3>

The given parameters are:

Weekly pocket = $28

Save = 20%

There are 52 weeks in a year.

So, the yearly pocket is:

Yearly pocket = $28 * 52

Evaluate

Yearly pocket = $1456

He saves 20%.

So, we have:

Savings = 20% * $1456

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Savings = $291.2

His spending is then calculated as:

Spending = $1456 - $291.2

Evaluate

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Hence, Welming's spending is $1164.8 and his savings is $291.2

Read more about percentage at:

brainly.com/question/843074

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2 years ago
A researcher obtains t = 2.35 for a repeated-measures study using a sample of n = 8 participants. Based on this t value, what is
ZanzabumX [31]

Answer:

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If we compare the p value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% or 1% of significance we fail to reject the null hypothesis.

Step-by-step explanation:

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided but we can assume it as \alpha=0.05. First we need to calculate the degrees of freedom like this:

df=n-1=8-1=7

The next step would be calculate the p value for this test.  Since is a bilateral test or two tailed test, the p value would be:  

p_v =2*P(t_{7}>2.35)=2*0.0255=0.051  

If we compare the p value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% or 1% of significance we fail to reject the null hypothesis.  

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3 years ago
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what did the doctor say?



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Answer:

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