We can treat each distance distance traveled by the four wheelers are vectors. Their sum must be zero since the last four wheeler truck ends up where the first four wheeler truck started
d1∠1 + d2∠2 + d3∠3 + d4∠4 + d5∠5 = 0
d5∠5 = - (d1∠1 + d2∠2 + d3∠3 + d4∠4)
Since we don't know the speed of the fifth wheeler, we just add the angles and equate it to 360
20 + 30 + 0 + -40 + ∠5 = 360
∠5 = 350 or -10
The fifth wheeler must travel at an angle of -10 degrees.
Ohh, Elimination Im doing that XD So its
Anwser - No Solution
Answer:
75
Step-by-step explanation:
after adding all the measures the sum give around 75, don't forget to add 11 ¾ in the left side
AC and AB are tangents to circle O, meaning that the angles C and B are right angles of 90 degrees. Since a quadrilateral's internal angles must sum up to 360 degrees, this means that A + B + C + O = 360
70 + 90 + 90 + O = 360
O = 110 degrees.
Answer:
50π cm²
Step-by-step explanation:
In this case we have that the area of the boomerang has been the area of the largest semicircle minus the area of the smaller semicircles.
We know that the radius is half the diameter:
r = d / 2 = 20/2
r = 10
Now we have to:
Alargest = π · r²
Alargest = π · (10 cm) ²
Alargest = 100π cm²
Asmaller = π · r²
Asmaller = π · (5 cm) ²
Asmaller = 25π cm²
Finally, the boomerang area has been:
Aboomerang = 100π cm² - 2 · (25π cm²)
Aboomerang = 50π cm²
